Question

The average height of an apple tree is 4.00 meters. How long would it take an apple falling from that height to reach the ground? Given: g = -9.8 meters/second2

Answer 1

Answer:

The time is 0.90 sec.

Explanation:

Given that,

Height = 4.00 m

We need to calculate the time

Using equation of motion

$s = ut+\dfrac{1}{2}gt^2$

Where, s = height

g = acceleration due to gravity

t = time

Put the value into the formula

$4.00=0+\dfrac{1}{2}\times9.8\times t^2$

$t^2=\dfrac{4.00\times2}{9.8}$

$t=\sqrt{\dfrac{4.00\times2}{9.8}}$

$t=0.90\ sec$

Hence, The time is 0.90 sec.

Answer 2

(9.8m/s) divided by 4m. the m's cancel out leaving you with s so 2.45s