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pishuonlain [190]

3 years ago

8

True or false: The quantity represented by theta_0 is a function of time (i.e., is not constant).

2 answers:

Lapatulllka [165]3 years ago

6 0

It is a measure of an angle

Mumz [18]3 years ago

6 0

It may be constant in some expressions and variable in others.
We don't how you'[re using it.

The same symbol may be used to represent any quantity you want
in any expression you write, as long as you make clear exactly what
it represents.

There's no mystical reason why the Greek letter π must always represent
3.14159... , or why the Greek letter Θ must always represent an angle, or
why the letter 'g' must always represent acceleration due to gravity.

When we see how you've used theta, we can determine whether it's
a constant or a function of time in that expression.

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An object accelerates 3 m/s2 , when a force of 6 N acts on it. What is the object’s mass

telo118 [61]

Answer:

<h2>2 kg</h2>

Explanation:

The mass of the object can be found by using the formula

$m = \frac{f}{a} \\$

f is the force

a is the acceleration

From the question we have

$m = \frac{6}{3} \\ = 2$

We have the final answer as

<h3>2 kg</h3>

Hope this helps you

3 0

3 years ago

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Anika [276]

Answer:

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8 0

3 years ago

A sample of gas in a syringe releases heat to its surroundings while the

blsea [12.9K]

Answer: b

Explanation:

When heat is released by the system i.e. system loses heat. So, we take it as negative -Q

When the work is done on the system then it is considered as negative work on the system i.e. -W

In this case, the plunger is pulled out, and work is done on the system. So, we take work as negative work -W

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3 0

3 years ago

Read 2 more answers

What is a neutral atom?

IgorC [24]

A neutral atom is simply an atom that has no charge.

8 0

3 years ago

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If a steady-state heat transfer rate of 3 kW is conducted through a section of insulating material 1.0 m2 in cross section and 2

kaheart [24]

Answer:

$\Delta T = \frac{3000 W *0.025 m}{1 m^2 (0.2 \frac{W}{mK})}= 375 K$

So then the difference of temperature across the material would be $\Delta T = 375 K$

Explanation:

For this case we can use the Fourier Law of heat conduction given by the following equation:

$Q = -kA \frac{\Delta T}{\Delta x}$ (1)

Where k = thermal conductivity = 0.2 W/ mK

A= 1m^2 represent the cross sectional area

Q= 3KW represent the rate of heat transfer

$\Delta T$ is the temperature of difference that we want to find

$\Delta x=2.5 cm =0.025 m$ represent the thickness of the material

If we solve $\Delta T$ in absolute value from the equation (1) we got:

$\Delta T =\frac{Q \Delta x}{Ak}$

First we convert 3KW to W and we got:

$Q= 3 KW* \frac{1000W}{1 Kw}= 3000 W$

And we have everything to replace and we got:

$\Delta T = \frac{3000 W *0.025 m}{1 m^2 (0.2 \frac{W}{mK})}= 375 K$

So then the difference of temperature across the material would be $\Delta T = 375 K$

5 0

4 years ago