Answer:
The answer is D
Explanation:
I'm too lz to explain everything.
sorry.
The conservation of energy always holds true even when not clearly observable in machines that are less than 100% efficient. More often than not a machine will suffer energy losses (e.g. consider for a cooling fan: friction between the rotating blades, drag resistance in the air the fan is pushing around, resistance in the wire, and heat radiating/conducting away from the circuitry).
Ammonia because it doesn't have nitrogen
Answer:
z = 93.2 m
Explanation:
We can appreciate that this expression is equivalent to the linear motion equation with constant acceleration
v² = v₀² + 2 a d
If we make a term-to-term comparison with the expression obtained, they are equivalent
u² = v² + 2 a z
From here we can clear the position
2 a z = u² –v²
z = (u² –v²) / 2 a
Let's calculate
For the speed to reduce the acceleration must be negative
z = (0 - 21.8²) / 2(- 2.55)
z = 93.2 m
Answer:
a) R₁ = 14.1 Ω, b) R₂ = 19.9 Ω
Explanation:
For this exercise we must use ohm's law remembering that in a series circuit the equivalent resistance is the sum of the resistances
all resistors connected
V = i (R₁ + R₂)
with R₁ connected
V = (i + 0.5) R₁
with R₂ connected
V = (i + 0.25) R₂
We have a system of three equations with three unknowns for which we can solve it
We substitute the last two equations in the first
V = i (
)
1 = i (
)
1 = i (
) =
i² + 0.75 i + 0.125 = 2i² + 0.75 i
i² - 0.125 = 0
i = √0.125
i = 0.35355 A
with the second equation we look for R1
R₁ =
R₁ = 12 /( 0.35355 +0.5)
R₁ = 14.1 Ω
with the third equation we look for R2
R₂ =
R₂ =
R₂ = 19.9 Ω