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olchik [2.2K]
3 years ago
14

Which equation has both a liquid and a gas as products? 2 upper H g upper O (s) right arrow 2 upper H g (l) plus upper O subscri

pt 2 (g). 2 upper M g (s) plus upper O subscript 2 (g) right arrow 2 upper M g upper O (s). 1 UJpper K upper C l upper O subscript 3 (s) right arrow 2 upper K upper C l (s) plus 3 upper O subscript 2 (g). Upper M g (s) plus 2 upper H upper C l (a q) right arrow upper H subscript 2 (g) plus upper M g upper C l subscript 2 (a q).
Chemistry
2 answers:
Mandarinka [93]3 years ago
8 0
<h2>Let us predict the gas and liquid products in option </h2>

Explanation:

option  1 :  2 upper H g upper O (s) right arrow 2 upper H g (l) plus upper O subscript 2 (g).

Chemical reaction

It is the reactants react to form products .

Chemical equation

It is the method of representing reaction in terms of moles , specifying states , symbols , molecular formulas etc .

This actually gives the complete info about the reaction .

In the above asked question or any other question we can specify the states by writting :

Solid as "S".

Liquid as "L"

Gas as (g).

inessss [21]3 years ago
8 0

Answer:

A

Explanation:

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True or False: In every gram of sucrose (table sugar) there is 0.513 g of oxygen
Ber [7]

Answer:

True

Explanation:

Step 1: Find molecular formula of sucrose

C₁₂H₂₂O₁₁

Step 2: Convert moles of oxygen present to grams

1 mol O = 16 g O

11 mol O = 176 g O

Step 3: Find molar mass of sucrose

C - 12.01 g/mol

H - 1.01 g/mol

O - 16.00 g/mol

12.01(12) + 22(1.01) + 11(16.00) = 342.34 g/mol C₁₂H₂₂O₁₁

Step 4: Set up dimensional analysis

1 gC_{12}H_{22}O_{11}(\frac{176 gO}{342.34gC_{12}H_{22}O_{11}} )

Step 5: Multiply/Divide and cancel out units

Grams of C₁₂H₂₂O₁₁ and grams of C₁₂H₂₂O₁₁ cancel out.

We are left with grams Oxygen

176/342.34 = 0.514109 grams Oxygen

4 0
3 years ago
Initially, a 55.0 liter compressible container, holding 2.4 moles of a gas, exerts a pressure of 760 millimeters of mercury at a
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