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Sunny_sXe [5.5K]
3 years ago
11

Calculate the dipole moment for hf (bond length 0.917 å), assuming that the bond is completely ionic.

Chemistry
1 answer:
Gwar [14]3 years ago
7 0
The dipole moment  =  [the charge magnitude at one of the ends (you can choose either one)] [the distance between charges]
It is usually calculated in SI units of Debye which represents the positive and negative charges separated by 0.2082 angestron

Thus,
dipole moment = 0.917/0.2082 = 4.4044 debye.
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The balanced chemical reaction is:

<span>Ca + Cl2 =  CaCl2
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We are given the amount of calcium metal to be used for this reaction. This will be the starting point for the calculations.

56 g Ca ( 1 mol Ca / 40.08 g Ca) (1 mol Cl2 / 1 mol Ca) ( 22.414 L Cl2 / 1 mol Cl2 ) = 31.32 L Cl2 gas produced from the reaction
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3 years ago
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c

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2 years ago
how many grams of oxygen are produced if 25.0g of potassium chlorate decomposes according to the reaction 2KCLO3 —-&gt; 2KCL +3O
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Answer:

approximately 15.1 grams.

Explanation:

The key to chemistry is to change everything to moles. Then when you have the answer in moles change the answer back to grams, liters, or whatever you want.

change 25 grams of potassium chlorate to moles.

calculate the gram molecular mass of potassium chlorate.

Chlorate is Cl with 3 oxygens. ate = saturated. Chlorine has seven valance electrons when it is saturated six of these electrons are used by oxygen ( 2 electrons per oxygen) leaving only 1 electron.

1 K x 39 grams/mole

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+3 O x 16 grams/ mole

= 122.4 grams / mole Potassium Chlorate

25

122.4

= moles.

2.05 moles of Potassium Chlorate.

There is a 1:1 mole ratio. 1 mole of Potassium Chlorate will produce 1 mole of Potassium Chloride.

2.05 moles of Potassium Chlorate will produce 2.05 moles of Potassium Chloride.

Find the gram molecular mass of Potassium Chloride.

1 K x 39 = 39

+1 Cl x 35.4 = 35.4

= 74.4 grams / mole.

2.05 moles x 74.4 grams/ mole = 15.2 grams

Hope it helps :)

6 0
2 years ago
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We know that two rods are conductors of electricity.

Now, suppose the case where rods Z and Y are the ones that conduct electricity, this means that X does not conduct electricity, then when the current reaches to X it stops (because X does not conduct) then the electricity never reaches the rods Z and Y, and then the electricity never reaches the bulb, but we know that the bulb lights up, so we must have that X is one of the conducting rods.

Then, if for example, Y does not conduct electricity, the electricity still can run through the Z rod and eventually reach the bulb.

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4 0
3 years ago
4 Infer is the reaction below possible?
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No, because hydrogen isn’t brought out of the equation
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