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3 years ago

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An object is (starting at rest) begins to plummet towards the earth. Assuming it is in a vacuum, how fast is the object travelin

g after 5s?

1 answer:

Eva8 [605]3 years ago

8 0

Answer:

–50.96

Explanation:

The following data were obtained from the question:

Initial velocity (Vᵢ) = 0 m/s

Acceleration (a) = – 9.8 m/s²

Time (t) = 5.2 s

Final velocity (Vբ) =.?

Acceleration is simply defined as the change of velocity with time. Mathematically, it is expressed as:

Acceleration (a) = Final velocity (Vբ) – Initial velocity (Vᵢ) /Time (t) =

a = (Vբ – Vᵢ) / t

With the above formula, we can determine how fast the object is traveling after 5 s as follow:

Initial velocity (Vᵢ) = 0 m/s

Acceleration (a) = – 9.8 m/s²

Time (t) = 5.2 s

Final velocity (Vբ) =.?

a = (Vբ – Vᵢ) / t

– 9.8 = (Vբ – 0) / 5.2

– 9.8 = Vբ / 5.2

Cross multiply

Vբ = –9.8 × 5.2

Vբ = –50.96 m/s

Therefore, the object is traveling at

–50.96 m/s

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Explanation:

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