Answer:
–50.96
Explanation:
The following data were obtained from the question:
Initial velocity (Vᵢ) = 0 m/s
Acceleration (a) = – 9.8 m/s²
Time (t) = 5.2 s
Final velocity (Vբ) =.?
Acceleration is simply defined as the change of velocity with time. Mathematically, it is expressed as:
Acceleration (a) = Final velocity (Vբ) – Initial velocity (Vᵢ) /Time (t) =
a = (Vբ – Vᵢ) / t
With the above formula, we can determine how fast the object is traveling after 5 s as follow:
Initial velocity (Vᵢ) = 0 m/s
Acceleration (a) = – 9.8 m/s²
Time (t) = 5.2 s
Final velocity (Vբ) =.?
a = (Vբ – Vᵢ) / t
– 9.8 = (Vբ – 0) / 5.2
– 9.8 = Vբ / 5.2
Cross multiply
Vբ = –9.8 × 5.2
Vբ = –50.96 m/s
Therefore, the object is traveling at
–50.96 m/s
