Answer:
0.045 J
Explanation:
The work done on a charge moving through a potential difference is given by
where
W is the work done
q is the charge
is the potential difference
In this problem, we have
q = 0.0050 C is the charge
is the potential difference
Using the formula, we find the work done:
<span>when two hydrogen atoms approach each other the potential energy of the combination becomes lower and lower until it reaches a minimum value of -436 kl/mol at a distance of 75 pm</span>
Kinetic energy = 1/2 * mass * velocity^2
In this case,
KE = 1/2 * 1569 kg * (15 (m/s))^2 = 176,5 kN
Answer:
In this scenario adding the dielectric material in between the plates will have no effect on the capacitance of the plates since the voltage remains unchanged
Explanation:
Normally Introducing a dielectric into a capacitor decreases the electric field, which decreases the voltage, which increases the capacitance.
A capacitor with a dielectric stores the same charge as one without a dielectric, but at a lower voltage.
Voltage and capacitance are inversely proportional when charge is constant.
Now in this case the voltage remains the same hence the charges remain the same also because voltage is inversely proportional to capacitance
