Question

Train is traveling at an initial velocity of 68.325m/s. After 23.75 seconds it speeds up to a final velocity of 79.32m/s. What is the train's acceleration during this time

Answer 1

So,

We know that:
$acceleration = \frac{ final\ velocity\ -\ initial\ velocity}{time}$

Plug in the values.
$acceleration = \frac{79.32 m/s^{2}\ -\ 68.325m/s^{2}}{23.75 secs}$
$acceleration = \frac{10.995m/s^{2} }{23.75 secs}$
$acceleration = 0.4629 m/s^{2}$