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babymother [125]
3 years ago
15

Train is traveling at an initial velocity of 68.325m/s. After 23.75 seconds it speeds up to a final velocity of 79.32m/s. What i

s the train's acceleration during this time
Physics
1 answer:
wariber [46]3 years ago
8 0
So,

We know that:
acceleration =  \frac{ final\ velocity\ -\ initial\ velocity}{time}

Plug in the values.
acceleration =  \frac{79.32 m/s^{2}\ -\ 68.325m/s^{2}}{23.75 secs}
acceleration =  \frac{10.995m/s^{2} }{23.75 secs}
acceleration = 0.4629 m/s^{2}
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Answer: is option C: <em>Prolonged periods of cooling and warming</em>.

Explanation:

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Virty [35]

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