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babymother [125]
3 years ago
15

Train is traveling at an initial velocity of 68.325m/s. After 23.75 seconds it speeds up to a final velocity of 79.32m/s. What i

s the train's acceleration during this time
Physics
1 answer:
wariber [46]3 years ago
8 0
So,

We know that:
acceleration =  \frac{ final\ velocity\ -\ initial\ velocity}{time}

Plug in the values.
acceleration =  \frac{79.32 m/s^{2}\ -\ 68.325m/s^{2}}{23.75 secs}
acceleration =  \frac{10.995m/s^{2} }{23.75 secs}
acceleration = 0.4629 m/s^{2}
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E14. A ball rolls off a table with a horizontal velocity of 5 m/s. If
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a) Vertical velocity: 5.9 m/s

b) Horizontal velocity: 5 m/s

Explanation:

a)

The motion of the ball is the motion of a projectile, which consists of two independent motions:

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- A uniformly accelerated motion (constant acceleration) along the vertical direction

Here we want to find the vertical component of the ball's velocity. This can be done by using the suvat equation for the vertical motion:

v_y = u_y +gt

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b)

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8 0
3 years ago
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Answer:

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