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KIM [24]
2 years ago
10

A certain part of the electromagnetic spectrum ranges from 200 nm to 400 nm. what is the lowest frequency associated with this p

ortion of the spectrum? (c 3.00 108 m/s)
Physics
1 answer:
IrinaK [193]2 years ago
5 0
The lowest and highest wavelengths of this part of the electromagnetic spectrum are:
\lambda_1 = 200 nm=200 \cdot 10^{-9} m
\lambda_2 = 400 nm = 400 \cdot 10^{-9} m

We can calculate the corresponding frequencies by using:
f= \frac{c}{\lambda}
where c is the speed of light. If we use this equation, we find:
f_1 = \frac{c}{\lambda_1}= \frac{3 \cdot 10^8 m/s}{200 \cdot 10^9 m} =1.5 \cdot 10^{15}Hz
f_2 = \frac{c}{\lambda_2}= \frac{3 \cdot 10^8 m/s}{400 \cdot 10^9 m} =7.5 \cdot 10^{14}Hz
Therefore, the lowest frequency associated with this portion of the spectrum is 
f_2 = 7.5 \cdot 10^{14} Hz

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A freight car with a mass of 10 metric tons is rolling at 108 km/h along a level track when it collides with another freight car
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Answer:

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Explanation:

Using the Principle of Conservation of Linear Momentum which states that the total momentum of a system is constant in any direction in which no external force acts.

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u2 = initial velocity of

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substituting valves in expression give

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1080( Mg x km/hr) + 0 = 360 (Mg x Km/h) + 36m2 (km/h)

1080 (Mgx km/hr) - 360(Mg x km/h) = 36m2 (km/h)

720(Mg x km/h) = 36m2 (km/h)

divide both side by  36 (km/h) gives

m2 = 20Mg =20 metric tons

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