Answer:
by heart beat camel lives
The complete balanced chemical reaction for this is:
C6H8O7 + 3 NaHCO3 ---> 3 H2O + 3 CO2 + Na3C6H5O7
First calculate for the number of moles of each reactant.
moles C6H8O7 = 1 g / (192.124 g / mol) = 5.2 * 10^-3 mol
moles NaHCO3 = 1 g / (84.01 g / mol) = 11.9 * 10^-3 mol
A. The ratio of the reactant from the chemical reaction
is 3NaHCO3:1C6H8O7, while the given chemicals are in the ratio of:
11.9 * 10^-3NaHCO3: 5.2 * 10^-3 C6H8O7 =
2.29NaHCO3:1C6H8O7
Therefore this means that there is less amount of NaHCO3
supplied than what is required therefore the limiting reactant is:
NaHCO3
B. We calculate based on the limiting reactant.
mass CO2 = 11.9 * 10^-3 mol NaHCO3 (3 mol CO2/1 mol
NaHCO3) (44.01 g/mol)
mass CO2 = 1.57 g
C. I believe what is asked here is the amount of excess
reactant which remains. The excess reactant is C6H8O7.
mass C6H8O7 left = [5.2 * 10^-3 mol – (11.9 * 10^-3 mol
NaHCO3 (1 mol C6H8O7/ 3 mol NaHCO3))] * (192.124 g / mol)
mass C6H8O7 left = 0.237 g
Answer:
0.074 moles
Explanation:
For every mole (of any element), there are 6.022 x 10^23 atoms.
There are 4.45 x 10^22 atoms of iron.
To find the moles we divide the number of atoms by Avogadro's number
4.45 x 10^22 / 6.022 x 10^23 = 0.0738957
Don't forget sig figs
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