Formal Charge is calculated as, Lewis structure is attached below,

Formal Charge = [# of valence electrons] - [electrons in lone pairs + 1/2 the number of bonding electrons]

# of valence electrons of Cl = 7

electrons in lone pairs = 4

number of bonding electrons = 6

Formal Charge = [7] - [4 + 6/2]

Formal Charge = [7] - [4 + 3]

Formal Charge = [7] - [7]

Formal Charge = 0

Result:
Formal charge on Cl in ClF₃ is zero.

4 0

3 years ago

131i has a half-life of 8.04 days. assuming you start with a 1.53 mg sample of 131i, how many mg will remain after 13.0 days ___

inn [45]

For this problem we can use half-life formula and radioactive decay formula.

Half-life formula,
t1/2 = ln 2 / λ

where, t1/2 is half-life and λ is radioactive decay constant.
t1/2 = 8.04 days

Hence,
8.04 days = ln 2 / λ
λ = ln 2 / 8.04 days

Radioactive decay law,
Nt = No e∧(-λt)

where, Nt is amount of compound at t time, No is amount of compound at t = 0 time, t is time taken to decay and λ is radioactive decay constant.

Nt = ?
No = 1.53 mg
λ = ln 2 / 8.04 days = 0.693 / 8.04 days
t = 13.0 days

By substituting,
Nt = 1.53 mg e∧((-0.693/8.04 days) x 13.0 days))
Nt = 0.4989 mg = 0.0.499 mg

Hence, mass of remaining sample after 13.0 days = 0.499 mg

The answer is "e"

8 0

2 years ago

Someone help please i am stuck on this

daser333 [38]

Answer:

33.5

Explanation:

the lowest point which is 33.5

pls mark brainlest

8 0

2 years ago