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Zarrin [17]
3 years ago
9

An extremely efficient enzyme called "efficase" catalyzes the conversion of "A" to "B." A researcher decides to mutate the enzym

e in order to try to improve its performance. Following active site mutations, a significant reduction in the value of KM and Vmax was observed. Which of the following may have occurred?
A) The affinity of the enzyme for the substrate was increased to a point which did not favor propagation (continuation) of the reaction.B) The decrease in V max was not related to the decrease in K M .C) If the reaction was first-order, the change in K M cannot have affected V max .D) The stability of E+S (E+A as written above) was increased, thereby increasing the K M .E) The reverse reaction (breakdown of EA to E+A) was favored, slowing the V max .
Biology
1 answer:
Nady [450]3 years ago
4 0

Answer:

E) The reverse reaction (breakdown of EA to E+A) was favored, slowing the V max .

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When plates collide or undergo subduction (that is – ride one over another), the plates tend to buckle and fold, forming mountains. Most of the major continental mountain ranges are associated with thrusting and folding or orogenesis. Examples are the Jura and the Zagros mountains.

Explanation:

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Phospholipids are the main component of which of the following organelles?
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During which phase of the cell cycle does the cell prepare for mitosis?
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The second growth phase

Explanation:

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6 0
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Diseases such as diphtheria result from a process called lysogenic conversion in which viral dna is integrated into a bacterial
bazaltina [42]
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6 0
3 years ago
if the ratio of the ages of kisii and esinam is 3:5 and that of Esinam and Larry is 3:5 and the sum of the ages of all three is
larisa [96]

Answer:

The age difference between the oldest and the youngest is 48.

Explanation:

Given the following data;

The ratio of the ages of Kisii (K) and Esinam (E) is 3:5.

The ratio of the ages of Esinam (E) and Larry (L) is 3:5.

The sum of the ages of all three is 147.

Since the age of Esinam is common in both ratios, we find the lowest common multiple (LCM);

LCM of 3,5 = 15.

Hence, the ratio of the three ages is now;

K:E:L = 9:15:25

Let their ages be denoted by x;

K:E:L = 9x:15x:25x

The sum of all three ages is;

9x + 15x + 25x = 147

49x = 147

x = 147/49

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To find the age difference between the oldest and the youngest;

The oldest is Esinam = 25x

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Therefore, 25x - 9x = 16x

Substituting the value of x, we have;

x = 3; 16x = 16(3) = 48.

The age difference between the oldest and the youngest is 48.

6 0
4 years ago
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