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3 years ago

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Anzelm wants to burn 540 calories while jogging. Jogging burns about 12 calories per minute. When Anzelm goes jogging, he usuall

y plans to stop and rest for about 5 minutes.

1 answer:

kondor19780726 [428]3 years ago

7 0

Answer:he will use 45 minutes to burn 540 calories . he spend a total of 50 minutes ie including 5 minutes of rest.

Step-by-step explanation: 1 minute burns 12 calories

Therefore 540÷12 = 45 minutes plus 5 minutes of rest = 50 minutes.

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Cindy bought 4 packets of onion seeds. Each packet contained 12 seeds. She planted 1 packet of the seeds, and 8 seeds sprouted.

olga55 [171]

Answer:

B because 8 seeds from pack 1. u do 8 times 3 other packs which is 24 So in between 20-30 seeds will sprout

7 0

3 years ago

For each of the following vector fields F , decide whether it is conservative or not by computing curl F . Type in a potential f

Phantasy [73]

The key idea is that, if a vector field is conservative, then it has curl 0. Equivalently, if the curl is not 0, then the field is not conservative. But if we find that the curl is 0, that on its own doesn't mean the field is conservative.

1.

$\mathrm{curl}\vec F=\dfrac{\partial(5x+10y)}{\partial x}-\dfrac{\partial(-6x+5y)}{\partial y}=5-5=0$

We want to find $f$ such that $\nabla f=\vec F$ . This means

$\dfrac{\partial f}{\partial x}=-6x+5y\implies f(x,y)=-3x^2+5xy+g(y)$

$\dfrac{\partial f}{\partial y}=5x+10y=5x+\dfrac{\mathrm dg}{\mathrm dy}\implies\dfrac{\mathrm dg}{\mathrm dy}=10y\implies g(y)=5y^2+C$

$\implies\boxed{f(x,y)=-3x^2+5xy+5y^2+C}$

so $\vec F$ is conservative.

2.

$\mathrm{curl}\vec F=\left(\dfrac{\partial(-2y)}{\partial z}-\dfrac{\partial(1)}{\partial y}\right)\vec\imath+\left(\dfrac{\partial(-3x)}{\partial z}-\dfrac{\partial(1)}{\partial z}\right)\vec\jmath+\left(\dfrac{\partial(-2y)}{\partial x}-\dfrac{\partial(-3x)}{\partial y}\right)\vec k=\vec0$

Then

$\dfrac{\partial f}{\partial x}=-3x\implies f(x,y,z)=-\dfrac32x^2+g(y,z)$

$\dfrac{\partial f}{\partial y}=-2y=\dfrac{\partial g}{\partial y}\implies g(y,z)=-y^2+h(y)$

$\dfrac{\partial f}{\partial z}=1=\dfrac{\mathrm dh}{\mathrm dz}\implies h(z)=z+C$

$\implies\boxed{f(x,y,z)=-\dfrac32x^2-y^2+z+C}$

so $\vec F$ is conservative.

3.

$\mathrm{curl}\vec F=\dfrac{\partial(10y-3x\cos y)}{\partial x}-\dfrac{\partial(-\sin y)}{\partial y}=-3\cos y+\cos y=-2\cos y\neq0$

so $\vec F$ is not conservative.

4.

$\mathrm{curl}\vec F=\left(\dfrac{\partial(5y^2)}{\partial z}-\dfrac{\partial(5z^2)}{\partial y}\right)\vec\imath+\left(\dfrac{\partial(-3x^2)}{\partial z}-\dfrac{\partial(5z^2)}{\partial x}\right)\vec\jmath+\left(\dfrac{\partial(5y^2)}{\partial x}-\dfrac{\partial(-3x^2)}{\partial y}\right)\vec k=\vec0$

Then

$\dfrac{\partial f}{\partial x}=-3x^2\implies f(x,y,z)=-x^3+g(y,z)$

$\dfrac{\partial f}{\partial y}=5y^2=\dfrac{\partial g}{\partial y}\implies g(y,z)=\dfrac53y^3+h(z)$

$\dfrac{\partial f}{\partial z}=5z^2=\dfrac{\mathrm dh}{\mathrm dz}\implies h(z)=\dfrac53z^3+C$

$\implies\boxed{f(x,y,z)=-x^3+\dfrac53y^3+\dfrac53z^3+C}$

so $\vec F$ is conservative.

4 0

3 years ago

Help with number 6 pleaseeeeeeee

vitfil [10]

SinA=5root3/10
CosA=5/10
TanA=5root3/5=root3
SinC=5/10=1/2=0.5
CosC=5root3/10
Tanc=5/5root3=1/root3

7 0

3 years ago

Si el largo de un rectángulo mide el doble del ancho que es "a", ¿cuál es su área?

rosijanka [135]

Answer:

El área es 2 veces el cuadrado del ancho del rectángulo.

Step-by-step explanation:

El área de un rectángulo viene dado por:

$A = a*l$

En donde:

a: es el ancho

l: es el largo

Si el largo es el doble del ancho:

$l = 2a$

Entonces el área es:

$A = a*l = a*(2a) = 2a^{2}$

Por lo tanto, el área es 2 veces el cuadrado del ancho del rectángulo.

Espero que te sea de utilidad!

6 0

3 years ago

What is the area of the actual square window

Naily [24]

Answer: 2.25 meters

Step-by-step explanation: 1 in = 2 meters. 0.75 is 75 percent of 1 so the length of the window is 75 percent of 2 which is 1.5. 1.5 squared is 2.25 so the length of the window is 2.25 meters

7 0

1 year ago