The table on the items produced by this company and the profits derived from these goods shows that the best model is y = -1.026x² + 1,016.402x - 162,075.
<h3>Which model best represents the data?</h3><h3 />
Find out the best model by testing all models assuming a given value of x. The model that gives a y value closest to the actual value is the best model.
Assuming x is 100:
= -1.026x² + 1,016.402x - 162,075
= (-1.026 x 100²) + (1,016.402 x 100) - 162,075
= -$70,694.80
Second model:
= -1.036x² + 1024.771x - 163710
= (-1.036 x 100²) + 1024.771 x 100 - 163710
= -$71,593
Third model:
= 298.214x - 66317.667
= 298.214 x 100 - 66317.667
= -$36,496.27
Fourth model:
= 196.2x - 18710
= 196.2 x 100 - 18,710
= $910
The best model is therefore the first model which shows the closest value to the actual y value of -$70,500 when x is 100.
Find out more on fitting models at brainly.com/question/2564940.
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Answer:
domain: {x | x is a real number}
range: {y l y> -8}
Step-by-step explanation:
f(x) = 4x² – 8 is a parabola, a U shape.
Since the stretch factor, 4, is positive, it opens up, there it will have a minimum value, the lowest point in the parabola.
y > -8 because the minimum is -8.
Parabolas do not have restricted "x" values. "4" does not restrict x because it is the stretch factor, which determines how wide the parabola is.
Quadratic standard form:
f(x) = ax² + bx + c
"a" represents how wide the graph is. If it's negative it opens down, if it's positive it opens up.
"b", if written, tells you it is not centred on the y-axis. It is not written, so the vertex is on the y-axis.
"c" is the y-intercept. In this case, since b = 0, it is also the minimum value.
This graph is a correct representation of the given quality! What I did was plug it into this online graphing calculator called desmos, you can use that!!
Answer:
None of them
Step-by-step explanation:
-16 y+13
16(−y+2) = -16 +32
−16(−y+13)
= 16y -208
−16(y+2) = -16y -32
16(−y+13)= -16y+208