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Masja [62]
2 years ago
14

Hi. i need help with this. i lack with this subject

Chemistry
2 answers:
Vesnalui [34]2 years ago
8 0

Answer: It's the circulatory system

Explanation:

Marat540 [252]2 years ago
5 0

Answer:

It's the circulatory system

Explanation:

hope it helps you

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The average rate of consumption of br− is 1.86×10−4 m/s over the first two minutes. what is the average rate of formation of br2
Scorpion4ik [409]
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7 0
2 years ago
Calculate the pOH of an aqueous solution of .0.073 M LiOH
Novosadov [1.4K]

Considering the definition of pOH and strong base, the pOH of the aqueous solution is 1.14

The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution and indicates the concentration of ion hydroxide (OH-).

pOH is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

On the other hand, a strong base is that base that in an aqueous solution completely dissociates between the cation and OH-.

LiOH is a strong base, so the concentration of the hydroxide will be equal to the concentration of OH-. This is:

[LiOH]= [OH-]= 0.073 M

Replacing in the definition of pOH:

pOH= -log (0.073 M)

<u><em>pOH= 1.14 </em></u>

In summary, the pOH of the aqueous solution is 1.14

Learn more:

  • <u>brainly.com/question/16032912?referrer=searchResults </u>
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7 0
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