Base your answer on the information below. The hydrocarbon 2-methylpropane reacts with iodine as represented by the balanced equ
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0.010 M solution of hydrochloric acid, HCl has a pH of 2.00 but a 0.010 M solution of acetic acid, HCH₃COO, is 3.37 is because HCl dissociates more.
<h3>Dissociation</h3>This is the separation of ions of an ionic compound when it dissolves.
<h3>Hydrogen ion concentration of HCl</h3>Since 0.010 M solution of hydrochloric acid, HCl has a pH of 2.00 its hydrogen ion concentration is gotten from
pH = -log[H⁺]
So,
So, [H⁺] = 10⁻²
<h3>Hydrogen ion concentration of HCH₃COO</h3>Also, since 0.010 M solution of acetic acid, HCH₃COO, has a pH of 3.37, its hydrogen ion concentration is gotten from
pH = -log[H⁺]
So,
So, [H⁺] = 10⁻³°³⁷ = 0.000427 = 4.27 × 10⁻⁴
Since the hydrogen ion concentration of HCl is 10⁻² and the hydrogen ion concentration of HCH₃COO is 4.27 × 10⁻⁴, we see that HCl dissociates more than HCH₃COO.
So, 0.010 M solution of hydrochloric acid, HCl has a pH of 2.00 but a 0.010 M solution of acetic acid, HCH₃COO, is 3.37 is because HCl dissociates more.
Learn more about dissociation here:
Answer:
The final temperature of the system is 42.46°C.
Explanation:
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
c = specific heat of water=
= mass of water sample with 100 °C= 50.0 g
= mass of water sample with 13.7 °C= 100.0 g
= final temperature of system
= initial temperature of 50 g of water sample=
= initial temperature of 100 g of water =
Now put all the given values in the given formula, we get
The final temperature of the system is 42.46°C.