Write the formula unit and the net-ionic equations to describe the reaction between potassium hydrogen phthalate (khp) and cesiu

Question

IRINA_888 [86]

3 years ago

11

Write the formula unit and the net-ionic equations to describe the reaction between potassium hydrogen phthalate (khp) and cesiu

m hydroxide.

Chemistry

2 answers:

dybincka [34] · Answer 1 · 2022-03-21T22:39:34+03:00

dybincka [34]3 years ago

8 0

C₆H₄(COOH)(COOK) + CsOH = C₆H₄(COOCs)(COOK) + H₂O

C₆H₄(COOH)(COO)⁻ + K⁺ + Cs⁺ + OH⁻ = C₆H₄(COO)₂²⁻ + K⁺ + Cs⁺ + H₂O

C₆H₄(COOH)(COO)⁻ + OH⁻ = C₆H₄(COO)₂²⁻ + H₂O

Alborosie · Answer 2 · 2022-03-22T00:42:30+03:00

Explanation:

The formula unit pf potassium phthalate is $C_6H_4(COOH)(COOK)$

The reaction between potassium hydrogen phthalate and cesium hydroxide.

$C_6H_4(COOH)(COOK)(aq)+CsOH(aq)\rightarrow C_6H_4(COOCs)(COOK)(aq)+H_2O(l)$

In the above reaction, proton will get combine with hydroxide ion from cesium hydroxide to form a water molecule.

$C_6H_4(COOH)(COO^-)(aq)+K^+(aq)+Cs^+(aq)+OH^-(aq)\rightarrow C_6H_4(COO^-)_2^{2-}(aq)+H_2O(l)+K^+(aq)+Cs^+(aq)$

Removing common ions from both sides :

The net ionic equation is :

$C_6H_4(COOH)(COO^-)(aq)+OH^-(aq)\rightarrow C_6H_4(COO^-)_2^{2-}(aq)+ H_2O(l)$