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IRINA_888 [86]
3 years ago
11

Write the formula unit and the net-ionic equations to describe the reaction between potassium hydrogen phthalate (khp) and cesiu

m hydroxide.

Chemistry
2 answers:
dybincka [34]3 years ago
8 0
C₆H₄(COOH)(COOK) + CsOH = C₆H₄(COOCs)(COOK) + H₂O

C₆H₄(COOH)(COO)⁻ + K⁺ + Cs⁺ + OH⁻ = C₆H₄(COO)₂²⁻ + K⁺ + Cs⁺ + H₂O

C₆H₄(COOH)(COO)⁻ + OH⁻ = C₆H₄(COO)₂²⁻ + H₂O

Alborosie3 years ago
6 0

Explanation:

The formula unit pf potassium phthalate is C_6H_4(COOH)(COOK)

The reaction between  potassium hydrogen phthalate and cesium hydroxide.

C_6H_4(COOH)(COOK)(aq)+CsOH(aq)\rightarrow C_6H_4(COOCs)(COOK)(aq)+H_2O(l)

In the above reaction, proton will get combine with hydroxide ion from cesium hydroxide to form a water molecule.

C_6H_4(COOH)(COO^-)(aq)+K^+(aq)+Cs^+(aq)+OH^-(aq)\rightarrow C_6H_4(COO^-)_2^{2-}(aq)+H_2O(l)+K^+(aq)+Cs^+(aq)

Removing common ions from both sides :

The net ionic equation is :

C_6H_4(COOH)(COO^-)(aq)+OH^-(aq)\rightarrow C_6H_4(COO^-)_2^{2-}(aq)+ H_2O(l)

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a laboratory procedure calls for making 510.0 mL of a 1.6 M KNO3 solution. How much KNO3 in grams is needed
barxatty [35]

Answer:

82.416 g of KNO ₃  is needed to produce 510.0 mL of a 1.6 M KNO ₃ solution.

Explanation:

Since molarity is the number of moles of solute that are dissolved in a given volume, calculated by dividing the moles of solute by the volume of the solution, the following rule of three can be applied: if in 1 L (1,000 mL) of KNO₃ there are 1.6 moles of the compound present, in 510 mL how many moles will there be?

moles=\frac{510 mL*1.6 moles}{1000 mL}

moles= 0.816

Being the molar mass of the elements:

  • K: 39 g/mole
  • N: 14 g/mole
  • O: 16 g/mole

So the molar mass of the compound KNO₃ is:

KNO₃= 39 g/mole + 14 g/mole + 3*16 g/mole= 101 g/mole

Now I can apply the following rule of three: if in 1 mole of KNO₃ there are 101 g, in 0.816 moles how much mass is there?

mass=\frac{0.816 moles*101 grams}{1 mole}

mass= 82.416 grams

<u><em>82.416 g of KNO ₃  is needed to produce 510.0 mL of a 1.6 M KNO ₃ solution.</em></u>

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Answer:

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Explanation:

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Assume a gasoline is isooctane, which has a density of 0.692 g/ml. What is the mass of 3.8 gal of the gasoline (1 gal = 3.78 l)?
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Density is the ratio of mass to the volume.

The mathematical expression is given as:

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Now, density of isooctane = 0.692 g/mL

Volume  = 3.8 gal

Since, 1 gallon = 3.78 L

So, 3.8 gal = 3.78 L\times 3.8

= 14.364 L

As, 1 L = 1000 mL

Therefore, 14.364 L= 14.364 L\times 1000 mL

Volume in mL = 14364 mL

Put the values,

0.692 g/mL=\frac{mass}{14364 mL}

m = 0.692 g/mL\times 14364 mL

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