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Ray Of Light [21]
3 years ago
12

Which describes the average velocity of an ant traveling at a constant speed

Physics
1 answer:
yanalaym [24]3 years ago
3 0

Answer: A. The total displacement divided by the time and  C. The slope of the ant's displacement vs. time graph.

Explanation:

Hi! The question seems incomplete, but I found the options on the internt:

A. The total displacement divided by the time.

B. The slope of the ant's acceleration vs. time graph.

C. The slope of the ant's displacement vs. time graph.

D. The average acceleration divided by the time.

Now, since we know the ant is travelling at a constant speed, its average velocity V will be expressed by the following equation:

V=\frac{d}{t}

Where:

d is the ant's total displacement

t is the time it took to the ant to travel to the kitchen

Hence one of the correct options is: A. The total displacement divided by the time

On the other hand, this can be expressed by a displacement vs. time graph graph, where the slope of that line leads to the equation written above. So, the other correct option is: C. The slope of the ant's displacement vs. time graph.

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A car drives 100 km north, 50 km east, then 10 km south. What is the car's displavement?​
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Answer:

\sqrt{ ({40}^{2} }  +  {50}^{2} ) =  \sqrt{(1600 + 2500)}  =  \sqrt{4100}  = 64.03

6 0
3 years ago
Which is a example of application of a scientific concept?
stira [4]
I think its c or d but im not quite sure.....
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A very long solid insulating cylinder has radius R = 0.1 m and uniform charge density rho0= 10-3 C/m3. Find the electric field a
Galina-37 [17]

Answer:

E   = (0.56 \times 10^8 ) r   \   \ N/c

Explanation:

Given that:

\rho_o = (10^{-3} ) \ c/m^3

R = (0.1) m

To find  the electric field for r < R by using Gauss Law

{\oint}E^{\to}* da^{\to} = \dfrac{Q_{enclosed}}{\varepsilon_o} --- (1)

For r < R

Q_{enclosed}=(\rho) ( \pi r^2 ) l

E*(2 \pi rl)= \dfrac{\rho ( \pi r ^2 l)}{\varepsilon_o}

E= \dfrac{\rho ( r)}{2 \varepsilon_o}

where;

\varepsilon_o = 8.85 \times 10^{-12}

E= \dfrac{10^{-3} ( r)}{2 (8.85 \times 10^{-12})}

E= \dfrac{10^{-3} ( r)}{2 (8.85 \times 10^{-12})}

E   = (0.56 \times 10^8 ) r   \   \ N/c

4 0
3 years ago
Does gravity increase or decrease with greater distance?
Karo-lina-s [1.5K]
Decrease. Gravity is stronger here on earth than on the moon.
3 0
3 years ago
Explain the relationships between gravity, mass, and distance.
Mazyrski [523]

Answer:

As the mass of an object increases, its gravitational force increases.

As an object's distance to other objects increases, its gravitational force on those objects increases.

Explanation:

The gravitational force of one object on another is calculated with the equation

F = (G*m1*m2)/(r²),

where G is the gravitational constant,

M1 and M2 are the masses of the two objects, and

r is the distance between them

We can see that the force has a direct relationship with both of the mass values, and an inverse square relationship with the distance between them.

Hope this helped!

7 0
3 years ago
Read 2 more answers
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