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nalin [4]
3 years ago
12

explain which properties of metals make sterling silver the best material for you to create hammered earrings.

Physics
1 answer:
7nadin3 [17]3 years ago
8 0

It is malleable

Explanation:

The property that makes metals such as sterling silver the best to create hammered earrings is their malleability.

All metals have a unique and fascinating property of being malleable. They can be carved into any of shape. When hammered they simply draw out and retain their long range ordering of their crystal lattice.

This is made possible by the presence of metallic bonding between the atoms.

  • The bulk of the physical properties of metals can be attributed the metallic bonds in them.
  • Metals have large sea of electrons in them.
  • In forming metallic bonds, there is an attraction between the positive nuclei of all the closely packed atoms in the lattice and the electron cloud jointly formed by all the atoms by loosing their outermost shell electrons.
  • Metals like silver have low ionization energy.
  • When they are hammered, they spread out the energy from the hammering.

learn more:

Metals brainly.com/question/2474874

#learnwithBrainly

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Explanation :

It is given that,

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Power dissipated,  P=0.064\ Watt

We know that the power dissipated is given by :

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I=\dfrac{P}{V}

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3 0
3 years ago
Read 2 more answers
A circular parallel plate capacitor is constructed with a radius of 0.52 mm, a plate separation of 0.013 mm, and filled with an
olya-2409 [2.1K]

Answer:

289282

Explanation:

r = Radius of plate = 0.52 mm

d = Plate separation = 0.013 mm

A = Area = \pi r^2

V = Potential applied = 2 mV

k = Dielectric constant = 40

\epsilon_0 = Electric constant = 8.854\times 10^{-12}\ \text{F/m}

Capacitance is given by

C=\dfrac{k\epsilon_0A}{d}

Charge is given by

Q=CV\\\Rightarrow Q=\dfrac{k\epsilon_0AV}{d}\\\Rightarrow Q=\dfrac{40\times 8.854\times 10^{-12}\times\pi \times (0.52\times 10^{-3})^2\times 2\times 10^{-3}}{0.013\times 10^{-3}}\\\Rightarrow Q=4.6285\times 10^{-14}\ \text{C}

Number of electron is given by

n=\dfrac{Q}{e}\\\Rightarrow n=\dfrac{4.6285\times 10^{-14}}{1.6\times10^{-19}}\\\Rightarrow n=289281.25\ \text{electrons}

The number of charge carriers that will accumulate on this capacitor is approximately 289282.

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