540 centigram is 0.054 hectograms
The current in the circuit drops and reduces, because of the higher voltage.
Because of the higher potential difference, the current in the circuit reduces as well.
Answer:
ρ₀ = 3λ/(2πR⁴)
Explanation:
If we take an elemental part of the cross sectional Area of the infinitely long cylinder.
The small elemental part has a small length dr in the cylinder's radial direction such that the cross sectional Area of the elemental part = 2πr dr
The linear density over the entire radial length of the cylinder will be equal to the sum of (volume charge density × elemental cross sectional Area)
That is,
λ = Σ ρ₀rR × 2πr dr
summing from 0 to R
λ = ∫ᴿ₀ (ρ₀rR × 2πr) dr
λ = ∫ᴿ₀ ρ₀R × 2πr² dr
λ = [ρ₀R × 2πr³/3 ]ᴿ₀
λ = (2π ρ₀R/3) [ r³ ]ᴿ₀
λ = (2π ρ₀R/3) [ R³ ]
λ = 2π ρ₀R⁴/3
ρ₀ = 3λ/(2πR⁴)
Answer:
a) 1.51Vm/s
b)Id=0.134A
Explanation:
(a) The time rate of change of electric flux between the plates can be computed by using:
where Ic is the current of the capacitor, e0 is the dielectric permittivity of vacuum and A is the area of the capacitor.
(b) The displacement current coincides with capacitor current:
Id = 0.134A
hope this helps!!
V=i*R (Ohm's Law)
If V = constant (power source)
When R increase, i decrease.
(More resistors=R increase)
V= potential
i=current
R=Resistance
Good luck!
M.