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julsineya [31]
2 years ago
12

How would you respond to a person who argued that the Big Bang theory is incorrect because it is only a theory and theories have

no scientific evidence backing them up?
Physics
2 answers:
Archy [21]2 years ago
8 0

I would respond by assuring the person that his understanding

of the scientific thing called a "theory" is all wrong, and that he

needs to do some research into the Scientific Method before he

maligns, denigrates, and insults scientists again. I would put some

real effort into convincing him that he is just shooting his mouth off,

and seriously doesn't know what he is talking about.


I know that this is the worst possible way to respond.

But these goons irritate me, and the easiest way to push my

anger button is to say something that has "only a theory" in it.

Also, I've had a bad day.

Umnica [9.8K]2 years ago
5 0

Well, you would reply that that's not what theories are. Theories explain the how and the why, laws explain the what. So, the Big Bang theory isn't "just a theory". It's a theory, it explains the how. (Also, if someone tells you it's anti-God or whatever, tell them the thoery was created by a Catholic scientist. True fact.) I hoped this helped!!! (You don't have the include who created the theory if this is for homework.)

You might be interested in
An unknown radioactive sample is observed to decrease in activity by a factor of two in a one hour period. What is its half-life
elena55 [62]

Answer:

The half-life is t_{1/2} = 1.005 h

Explanation:

Using the decay equation we have:

A=A_{0}e^{-\lambda t}

Where:

  • λ is the decay constant
  • A(0) the initial activity
  • A is the activity at time t

We know the activity decrease by a factor of two in a one hour period (t = 1 h), it means that A = \frac{A_{0}}{2}

\frac{A_{0}}{2}=A_{0}e^{-\lambda*1 h}

0.5=e^{-\lambda*1 h}

Taking the natural logarithm on each side we have:

ln(0.5)=-\lambda

\lambda=0.69 h^{-1}

Now, the relationship between the decay constant λ and the half-life t(1/2) is:

\lambda = \frac{ln(2)}{t_{1/2}}

t_{1/2} = \frac{ln(2)}{\lambda}

t_{1/2} = \frac{ln(2)}{0.69}

t_{1/2} = 1.005 h

I hope it helps you!

6 0
3 years ago
The motion of a particle is defined by the relation x 5 t 3 2 9t 2 1 24t 2 8, where x and t are expressed in inches and seconds,
shutvik [7]

Answer:

a)  t = 2.0 s,  b)  x_f = - 24.56 m,  Δx = 16.56 m

Explanation:

This is an exercise in kinematics, the relationship of position and time is indicated

          x = 5 t³ - 9t² -24 t - 8

a) ask when the velocity is zero

speed is defined by

         v = \frac{dx}{dt}

let's perform the derivative

        v = 15 t² - 18t - 24

        0 = 15 t² - 18t - 24

let's solve the quadratic equation

      t = \frac{18 \pm \sqrt{18^2 + 4 \ 15 \ 24}  }{2 \ 15}

       t = \frac{18 \pm 42}{30}

       t1 = -0.8 s

      t2 = 2.0 s

the time has to be positive therefore the correct answer is t = 2.0 s

b) the position and distance traveled for a = 0

acceleration is defined by

       a = dv / dt

       a = 30 t - 18

       a = 0

       30 t = 18

       t = 18/30

       t = 0.6 s

we substitute this time in the expression of the position

       

       x = 5 0.6³ - 9 0.6² - 24 0.6 - 8

       x = 1.08 - 3.24 - 14.4 - 8

       x = -24.56 m

we see that all the movement is in one dimension so the distance traveled is the change in position between t = 0 and t = 0.6 s

the position for t = 0

       x₀ = -8 m

the position for t = 0.6 s

      x_f = - 24.56 m

the distance

     ΔX = x_f - x₀

     Δx = | -24.56 -(-8) |

     Δx = 16.56 m

5 0
2 years ago
Which of the following statements is true about hydrothermal vents?
irina [24]
A because its about an opening in the sea floor and tectonic plates are the only thing.

7 0
3 years ago
Read 2 more answers
A dog walks 26m, East, 29m, West, and 7m, East. What is his displacement?
sergeinik [125]

Answer:

4m East

Explanation:

26-29= -3 (so that means 3m west)

-3+7= 4 (so 4m East)

hope it helps

7 0
3 years ago
A 40.0 kg physics student at rest on a frictionless rink throws a 3.0 kg box, giving the box a velocity of 8.0 m/s. Which statem
zvonat [6]

Answer: (b)

Explanation:

Given

mass of Student M=40 kg

mass of box m=3 kg

velocity of box v=8 m/s

suppose u is the velocity of the student after the throw

As there is no external force is applied so momentum is conserved

Initial momentum=final momentum=0

0=Mu+mv

Mu=-mv

u=-\frac{3}{40}\times 8=-\frac{3}{5}\\u=-0.6\ m/s

Here negative sign indicates the velocity is opposite in direction i.e. opposite to the direction of the box

6 0
2 years ago
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