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qaws [65]
3 years ago
5

The lasers are red, meaning that they are giving off light in the _____ region of the electromagnetic spectrum

Physics
2 answers:
Yanka [14]3 years ago
8 0
<span>The lasers are red, meaning that they are giving off light
in the longest wavelength part of the visible region of
the electromagnetic spectrum</span>
Softa [21]3 years ago
4 0

As per the question the color of laser light is given as red.

If we arrange all the electromagnetic waves in the decreasing order of frequency ,then the electromagnetic spectrum contains gamma ray as the first which is followed by all other electromagnetic waves according to their frequency.

The visible light ranges from 400 nm to 700 nm which contains sunlight i.e white colors with it's constituent colors starting from violet to red. The red color is the longest wavelength part of the visible region.

The wavelength of visible light is longer than ultraviolet wave but smaller than infrared radiation. Except the bisible region,the color of radiation is invisible to eye.


As per the question the color of emiited laser radiation is red .Hence it must lie in the visible region of the electromagnetic spectrum.



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A horizontal force acts on an object on a fric- tionless horizontal surface. If the force is halved and the mass of the object i
guapka [62]

(a)  If the force is halved and the mass of the object is doubled, the acceleration will be one-fourth as great.

(b)  if the force on it is doubled and its mass is halved, the new acceleration will be four times as great.

The force on an object is determined by applying Newton's second law of motion;

F = ma

\frac{F_1}{m_1a_1} = \frac{F_2}{m_2a_2}

(a)

when the force is halved, F₂ = 0.5F₁,

mass is doubled, m₂ = 2m₁

\frac{F_1}{m_1a_1} = \frac{0.5F_1}{2m_1a_2} \\\\2m_1a_2F_1 = 0.5F_1 m_1a_1\\\\2a_2 = 0.5a_1\\\\a_2 = \frac{0.5a_1}{2} = \frac{a_1}{2 \times 2} = \frac{a_1}{4} \\\\a_2 = \frac{1}{4} (a_1)

Thus, If the force is halved and the mass of the object is doubled, the acceleration will be one-fourth as great.

(b)

when the force is doubled, F₂ = 2F₁,

mass is halved, m₂ = 0.5m₁

\frac{F_1}{m_1 a_1} = \frac{2F_1}{0.5m_1 a_2} \\\\0.5m_1a_2 F_1 = 2F_1m_1a_1\\\\0.5a_2 = 2a_1\\\\a_2 = \frac{2a_1}{0.5} \\\\a_2 = 4(a_1)

Thus, if the force on it is doubled and its mass is halved, the new acceleration will be four times as great.

Learn more here:brainly.com/question/19887955

3 0
2 years ago
Air rushing against an airplane is an example of _____friction.
slava [35]
The word "static" would be known to be friction as air rushing against an airplane
6 0
3 years ago
3. The honeycomb-like appearance of this sandstone is a result of.
sladkih [1.3K]

Answer:

The answer is "Option C".

Explanation:

Wedging Freeze is generated by repeated freezing. Freeze wedging occurs, whenever the water is turned into ice as a result of the 9 percent expansion. When it freezes, cracks full of water are forced to separate further. and other options are incorrect, that can be described as follows:

  • In option A, It is a state where the element converts into a liquid, that's why it is not correct.
  • In option B, It is a reaction in which the bonds of water is divided into particular substance, that's why it is not correct.
  • In option D, It is a form of mechanical or physical rock weathering, that's it is not correct.

6 0
3 years ago
Read 2 more answers
A 55-kg woman is wearing high heels.
Grace [21]

Answer:

Pressure, P=1.90\times 10^7\ Pa        

Explanation:

It is given that,

Mass of the woman, m = 55 kg

Diameter of the circular cross section, d = 6 mm

Radius, r = 3 mm = 0.003 m

Let P is the pressure exerted on the floor. It is equal to the force acting on woman per unit area. It is given by :

P=\dfrac{F}{A}

P=\dfrac{mg}{\pi r^2}

P=\dfrac{55\times 9.8}{\pi (0.003)^2}

P=1.90\times 10^7\ Pa

So, the pressure exerted on the floor is 1.90\times 10^7\ Pa. Hence, this is the required solution.

7 0
3 years ago
4. A 1200 kg car traveling North at 20.0 m/s collides with a 1400 kg car traveling South at 22.0 m/s. The two
Dvinal [7]

Answer:-2.61 m/s

Explanation:

This problem can be solved by the Conservation of Momentum principle, which establishes that the initial momentum p_{o} must be equal to the final momentum p_{f}:

p_{o}=p_{f} (1)

Where:

p_{o}=mV_{o}+MU_{o} (2)

p_{f}=(m+M)V_{f} (3)

m=1200 kg is the mass of the first car

V_{o}=20 m/s is the velocity of the first car, to the North

M=1400 kg is the mass of the second car

U_{o}=-22 m/s is the mass of the second car, to the South

V_{f} is the final velocity of both cars after the collision

mV_{o}+MU_{o}=(m+M)V_{f} (4)

Isolating V_{f}:

V_{f}=\frac{mV_{o}+MU_{o}}{m+M} (5)

V_{f}=\frac{(1200 kg)(20 m/s)+(1400 kg)(-22 m/s)}{1200 kg+1400 kg} (6)

Finally:

V_{f}=-2.61 m/s (7) This is the resulting velocity of the wreckage, to the south

7 0
4 years ago
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