Answer:
The required probability is 
Step-by-step explanation:
The probability of obtaining a defective item from container 1 is 
The probability of obtaining a good item from container 1 is 
The probability of obtaining a defective item from container 2 is 
The probability of obtaining a good item from container 2 is 
The cases of the event are
1)Defective item is drawn from container 1 and good item is drawn from container 2
2)Defective item is drawn from container 2 and good item is drawn from container 1
Thus the required probability is the sum of above 2 cases
Answer: The first experiment has M probabilities, and the second has I(m) outcomes, that depends on the result of the first.
And lets call m to the result of the first experiment.
If the outcome of the first experiment is 1, then the second experiment has 1 possible outcome.
If the outcome of the first experiment is 2, then the second experiment has 2 possibles outcomes.
If the outcome of the first experiment is M, then the second experiment has M possibles outcomes.
And so on.
So the total number of combinations C is the sum of all the cases, where we exami
1 outcome for m = 1
+
2 outcomes for m=2
+
.
.
.
+
M outcomes for m = M
C = 1 + 2 + 3 + 4 +...´+M
Step-by-step explanation:
They want you to write a paragraph about addition, subtraction, multiplication, and division.
Divide number of people who would buy it again by total number surveyed them multiply by 100 for the percent.
1815/3300 = 0.55
0.55 x 100 = 55%
The answer is 55%
