Please: Use "^" to denote exponentiation: <span>2x^2 + 8x - 12 = 0

Reduce this by div. every term by 2: </span><span>x^2 + 4x - 6 = 0

Here a=1, b=4 and c = -6. Square half of b, obtaining (4/2)^2 = 4, and add, and then subtract, this 4 to x^2 + 4x - 6:

</span> x^2 + 4x +4 - 4 - 6 = 0. Rewrite the square as (x+2)^2, obtaining new equation

(x+2)^2 = 10. Take the sqrt of both sides: x+2 = plus or minus sqrt(10).

Finally, solve for x: x = -2 plus or minus sqrt(10).

8 0

3 years ago

seven different gifts are to be distributed among 10 children. How many distinct results are possible if no child is to receive

Alik [6]

Answer:

120 distinct results are possible if no child is to receive more than one gifts.

Step-by-step explanation:

When the order is not important, we use the combination formula:

$C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The order is said to be not important if for example, John receiving the Buffalo Bills jersey and then Laura receiving the Cleveland Browns jersey is the same as Laura receiving the Cleveland Browns jersey before John receives the Buffalo Bills jersey.

In this problem, we have that:

Combinations of 7 from a set of 10 elements. So

$C_{n,x} = \frac{n!}{x!(n-x)!}$

$C_{10,7} = \frac{10!}{7!(3)!} = 120$

120 distinct results are possible if no child is to receive more than one gifts.

6 0

2 years ago

So nobody is smart enough to answer my question?

Paha777 [63]

That is ver very sad

3 0

2 years ago

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