Answer:
25 grams
Explanation:
You strat off with 400 grams of your substance. By day 14, half has dcayed and you only have 200 grams left. By day 28, there are 100 grams of the substance. On day 42, there are 50 grams left. Finally, on day 56, the substance has been through four half-lives and 25 grams remain.
Answer:
0.256 L
Explanation:
We should use the following formula:
concentration (1) × volume (1) = concentration (2) × volume (2)
concentration (1) = 0.82 M NaOCl
volume (1) = ?
concentration (2) = 0.21 M NaOCl
volume (2) = 1 L
volume (1) = [concentration (2) × volume (2)] / concentration (1)
volume (1) = [0.21 / 1] / 0.82 = 0.256 L
The temperature the environment the fertilizer the amount of water how long you grow them for
Acids and Bases
Compound Formula % by Weight
Acetic acid, glacial CH3COOH 99.5
Formic acid HCOOH 90
Hydrochloric acid HCl 36
Nitric acid HNO3 71
The limiting reactant in the reaction would be the compound that would be consumed completely in the reaction. The balanced chemical reaction for this problem is written as:
<span>MnO2 + 4HCl → MnCl2 + 2H2O + Cl2
From the reaction and the amounts present of the reactant, the limiting reactant would be HCl or hydrochloric acid. Ten moles of HCl only need 2.5 moles of MnO2. Hope this helps.</span>