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Komok [63]
2 years ago
6

In which direction will the following equilibrium shift when solid sodium fluoride is added to an aqueous solution of acetic aci

d? CH3COOH â CH3COOâ + H+ A. The equilibrium shifts to the right, to form more products. B. The equilibrium shifts to the left, to form more reactants. C. There is no change; the system is still at equilibrium.
Chemistry
1 answer:
Sedbober [7]2 years ago
6 0

Answer:

A. The equilibrium shifts to the right, to form more products.

Explanation:

When sodium fluoride, NaF, is added to an aqueous solution, some HF is produced:

NaF + H₂O ⇄ OH⁻ + Na⁺ + HF.

That is, some H⁺ reacts decreasing its concentration.

Now, the equilibrium of the acetic acid is:

CH3COOH ⇄ CH3COO⁻ + H⁺

As the concentration of H⁺ decreases:

A. The equilibrium shifts to the right, to form more products.

In order to restore the initial equilibrium.

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It took 55 days for a radioactivity of 1.75 x 1012 Bq to remain 0.135 Ci. What is the half-life of this radioactivity?
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From the calculations, the half life of the material is 6.5 days.

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The term radioactivity has to do with the spontaneous disintegration of a specie.

Uisng the formula;

N=Noe^-kt

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Hence;

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