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Hitman42 [59]
3 years ago
5

A scientist wrote a report that communicates the steps he performed in an investigation, the data he gathered, and his conclusio

ns. A second scientist used the report to carry out the same investigation. However, her results were very different. Are the results of the investigation described below valid? If not, what should the scientists do next? Explain your reasoning.
Chemistry
1 answer:
Nookie1986 [14]3 years ago
4 0

Answer:

<u>yes, this is an acceptable practice in research.</u>

<u>Explanation:</u>

Note that, having a different result in one's research does not imply it is automatically invalid. However, because there may have been some errors or limitations in the previous work by the male researcher, it is possible that the later results are more accurate, even though she used the same procedures. She may have been more careful when calculating her results.

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CO2 + H2O - H2CO3<br> The reaction above is classified as
Elena L [17]

Answer:

Nonmetal oxides react with water to form oxyacids. Ex. CO2 + H2O → H2CO3 Page 3 Decomposition - compound (reactant) breaks down into 2 or more simpler substances.

3 0
3 years ago
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What is the average mass of a single silicon atom in grams?
torisob [31]

1 mol of Silicon = 28.0855 g (in average)

then

1 mol = 6.022*10^23 atoms

then

28.0855/(6.022*10^23) g/atom

4.66381*10^-23 g per atom


5 0
3 years ago
Finish this formula: Speed = _______ divided by time
Alexus [3.1K]

Answer:

Distance

Explanation:

Speed= Distance/ Time

7 0
3 years ago
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What is the wavenumber of the radiation emitted when a hydrogen
LUCKY_DIMON [66]

Answer: Wavenumber of the radiation emitted  is 0.08\times 10^{8}m^{-1}

Explanation:

The relationship between wavelength and energy of the wave follows the equation:

E=\frac{hc}{\lambda}

where,

E = energy of the radiation = 1.634\times 10^{-18}J

h = Planck's constant  = 6.626\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda = wavelength of radiation = ?

Putting values in above equation, we get:

1.634\times 10^{-18}J=\frac{(6.626\times 10^{-34}Js)\times (3\times 10^8m/s)}{\lambda}\\\\\lambda=12.16\times 10^{-8}m

\bar {\nu}=\frac{1}{\lambda}=\frac{1}{12.16\times 10^{-8}}=0.08\times 10^{8}m^{-1}

Thus wavenumber of the radiation emitted  is 0.08\times 10^{8}m^{-1}

8 0
3 years ago
What is the concentration of an unknown Mg(OH)2 solution if it took an average of 15.4mL of
vova2212 [387]

Answer:

0.077M

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

2HCl + Mg(OH)2 —> MgCl2 + 2H2O

From the balanced equation above,

The mole ratio of the acid (nA) = 2

The mole ratio of the base (nB) = 1

Step 2:

Data obtained from the question.

Concentration of base Cb =...?

Volume of base (Vb) = 10mL

Concentration of acid (Ca) = 0.1M

Volume of acid (Va) = 15.4mL

Step 3:

Determination of the concentration of the base, Mg(OH)2.

The concentration of the base can be obtained as follow:

CaVa/CbVb = nA/nB

0.1 x 15.4 /Cb x 10 = 2/1

Cross multiply to express in linear form

Cb x 10 x 2 = 0.1 x 15.4

Divide both side by 10 x 2

Cb = (0.1 x 15.4) /(10 x 2)

Cb = 0.077M

Therefore, the concentration of the base, Mg(OH)2 is 0.077M

7 0
3 years ago
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