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WINSTONCH [101]
3 years ago
8

Which element has the smallest atomic radius? calcium potassium scandium titanium

Chemistry
2 answers:
Alex787 [66]3 years ago
8 0

 The element  that has the smallest  atomic radius is  <u>titanium</u>


          <em><u>explanation</u></em>

  • Calcium,potassium,  scandium and titanium are in  period  4 in the periodic table.
  • Generally  the atomic   radius    decreases  across the period (from the left to the right) .  This is because  across the period  there is increase  in nuclear charge  which  make electrons been strongly attracted to the nuclear.
  • Titanium is in atomic number 22 thus it has  more nuclear  charge  that  calcium,potassium and  scandium therefore  titanium has the  smallest atomic radius.
nata0808 [166]3 years ago
8 0

Answer: Option (d) is the correct answer.

Explanation:

It is known that in a periodic table, atomic size decreases when we move from left to right.

The given elements potassium, calcium, scandium, and titanium all belongs to  third period.

Therefore, out of these elements potassium is at the extreme left and titanium is towards the right. Thus, we can conclude that titanium is the element which has the smallest atomic radius.

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jek_recluse [69]
Hydrogen, helium and oxygen
6 0
3 years ago
The equilibrium constant Kp for the reaction I2(g) + Br2(g) ⇀↽ 2 IBr(g) + 11.7 kJ is 280 at 150◦C. Suppose that a quantity of IB
mixas84 [53]

Answer:

\large \boxed{\text{0.0120 atm }}

Explanation:

The balanced equation is

I₂(g) + Br₂(g) ⇌ 2IBr(g)

Data:

      Kp = 280

p(IBr) = 0.200 atm

1. Set up an ICE table.

Let p = the initial pressure of IBr. Then

\begin{array}{ccccccc}\rm \text{I}_{2}& + & \text{Br}_{2} & \, \rightleftharpoons \, & \text{2IBr} &  &  \\0 & & 0 & & p & & \\+x &   & +x  & & -2x &   &\\x &   & x} &   & 280 & & \\\end{array}

2. Calculate p(I₂)

\begin{array}{rcl}K_{\text{p}}&=&\dfrac{p_{\text{IBr}}^{2}} {p_{\text{I}_2}^{2}}\\\\280&=&{\dfrac{0.200^{2}}{x^{2}}&&\\\\280x^{2} & = &0.0400\\x^{2} & = &\dfrac{0.0400}{280 }\\\\& = & 1.429 \times 10^{-4}\\x & = & \textbf{0.0120 atm}\\\end{array}\\\text{The partial pressure of iodine is $\large \boxed{\textbf{0.0120 atm }}$}}

Check:

\begin{array}{rcl}{\dfrac{0.200^{2}}{0.0120^{2}}}&=&280\\\\280& =& 280\\\end{array}

8 0
3 years ago
When water changes states from a liquid to gas , the water molecules move far apart . True or false? (6th grade science)
ella [17]

Answer:true

Explanation:

4 0
4 years ago
A student prepared several aqueous sodium chloride (NaCl) solutions to observe boiling point elevation at various molal concentr
NNADVOKAT [17]

The question is incomplete, the complete question is;

A student prepared several aqueous sodium chloride (NaCl) solutions to observe boiling point elevation at various molal concentrations, however, several errors were made throughout the procedure. Determine whether these errors would cause the observed boiling point to be increased or decreased relative to the expected boiling point, based on the procedure, or have no effect on the experimental results.

* The flask is washed with water but not thoroughly dried before preparing the solution

* The mass of NaCl used to prepare the solution is 5.400 grams instead of 4.400 grams

* Some of the prepared solution splashes out of the flask prior to observation of the boiling point

* When making the salt solution, 55.0 milliliters of water is added instead of 50.0 milliliters

Answer:

The flask is washed with water but not thoroughly dried before preparing the solution  - decrease

The mass of NaCl used to prepare the solution is 5.400 grams instead of 4.400 grams

-increase

Some of the prepared solution splashes out of the flask prior to observation of the boiling point- have no effect

When making the salt solution, 55.0 milliliters of water is added instead of 50.0 milliliters- decrease

Explanation:

If the flask is washed but not dried, then the solution will be further diluted than expected. As a result of this further dilution, the observed boiling point will be less than the expected boiling point because the boiling point depends on the solution's concentration.

If more solute is added than expected, the concentration of the solution is increased and the boiling point also increases above the expected boiling point due to the increase in amount of solute present.

If some of the solution splashes out of the flask prior to boiling, the boiling point is not affected because the concentration of the solution was not altered. The boiling point only changes when the concentration of the solution is changed.

If 55 ml of water is added instead of 50 ml, the solution is now more dilute than expected thereby reducing the concentration of the solution and the boiling point. Remember that, as the concentration of the solution decreases, the boiling point decreases accordingly.

8 0
3 years ago
What is the electron configuration for oxygen with a 2- charge (o2-)?
Juli2301 [7.4K]
Oxygen:
Atomic no. = 8(from periodic table)
⇒1s^2 2s^2 2p^4
But it is O^2-
There are 2 more electrons
=>1s^2 2s^2 2p^6
Voila!
3 0
3 years ago
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