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zaharov [31]
3 years ago
6

Which is the answer?

Chemistry
2 answers:
Digiron [165]3 years ago
8 0
I believe your answer is B, but im not completely sure
professor190 [17]3 years ago
3 0
The answer is B.Steel
You might be interested in
How many Na ions are in 2.7 g of NaCl?<br> Answer in units of ions.
Viefleur [7K]

Answer:

2.778 * 10^{22}

Explanation:

Weight of NaCl is equal to sum of weight of one mole of sodium and one mole of chloride.

Mathematically, it can be represented as -

1 mol (Na) + 1 mol (Cl) = 23.0  + 35.5  = 58.5 g/mol

In 58.5 gram of NaCl, there is one mole of Na or 6.02 * 10^{23} ions

In one gram of NaCl, there will be

\frac{6.02 * 10^{23}}{58.5} sodium ions

In 2.7 grams of  NaCl, the number of sodium ions will be -

\frac{6.02 * 10^{23}}{58.5} * 2.7

2.778 * 10^{22}

3 0
3 years ago
A galvanic (voltaic) cell has the generic metals X and Y as electrodes. X is more reactive than Y , that is, X more readily reac
Margaret [11]

Answer:

(1) cathode: Y

(2) anode X

(3) electrons in the wire flow toward: Y

(4) electrons in the wire flow away from: X

(5) anions from the salt bridge flow toward X

(6) cations from the salt bridge flow toward Y

(7) gains mass: Y

(8) looses mass X

Explanation:

The voltaic cell uses two different metal electrodes, each in an electrolyte solution. The anode will undergo oxidation and the cathode will undergo reduction. The metal of the anode will oxidize, going from an oxidation state of 0 (in the solid form) to a positive oxidation state, and it will become an ion. At the cathode, the metal ion in the solution will accept one or more electrons from the cathode, and the ion’s oxidation state will reduce to 0. This forms a solid metal that deposits on the cathode. The two electrodes must be electrically connected to each other, allowing for a flow of electrons that leave the metal of the anode and flow through this connection to the ions at the surface of the cathode. This flow of electrons is an electrical current that can be used to do work, such as turn a motor or power a light.

7 0
3 years ago
How many electrons can the n=4 shell hold?<br> a. 8b.16c.32d.64?
ra1l [238]
The maximum the fourth shell can have is 32.
6 0
3 years ago
Read 2 more answers
8. Estimate the maximum volume percent of Methanol vapor that can exist at standard conditions. Vapor pressure = 88.5 mm Hg in a
sashaice [31]

Explanation:

Vapor pressure is defined as the pressure exerted by vapors or gas on the surface of a liquid.

It is known that at standard condition, vapor pressure is 760 mm Hg.

And, it is given that methanol vapor pressure in air is 88.5 mm Hg.

Hence, calculate the volume percentage as follows.

                  Volume percentage = \frac{\text{given vapor pressure}}{\text{standard vapor pressure}} \times 100

                                                    = \frac{88.5}{760} \times 100

                                                    = 11.65%

Thus, we can conclude that the maximum volume percent of Methanol vapor that can exist at standard conditions is 11.65%.

6 0
3 years ago
How many grams of carbon are there in 706 grams of acetic acid
vova2212 [387]

Answer:

How many grams Acetic Acid in 1 mol? The answer is 60.05196.

We assume you are converting between grams Acetic Acid and mole?

(人◕ω◕)

Explanation:

You can view more details on each measurement unit:

molecular weight of Acetic Acid or mol

The molecular formula for Acetic Acid is CH3COOH.

The SI base unit for amount of substance is the mole.

1 grams Acetic Acid is equal to 0.016652245821785 mole.

Note that rounding errors may occur, so always check the results.

Use this page to learn how to convert between grams Acetic Acid and mole.

Examples

1 grams Acetic Acid to mol = 0.01665 mol

10 grams Acetic Acid to mol = 0.16652 mol

20 grams Acetic Acid to mol = 0.33304 mol

30 grams Acetic Acid to mol = 0.49957 mol

40 grams Acetic Acid to mol = 0.66609 mol

50 grams Acetic Acid to mol = 0.83261 mol

100 grams Acetic Acid to mol = 1.66522 mol

200 grams Acetic Acid to mol = 3.33045 mol

7 0
3 years ago
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