<span>12.7 g Li*(1 mole Li/6.94 g Li)=1.83 moles of Li
34.7 g N2(1 mole N2/28 g N2)=1.23
1.83 moles Li*(2 moles Li3N/6 mole Li)(34.82 grams Li3N/1 mole Li3N)=21.24g Li3N </span>
Answer:
a
Explanation:
Mixture is a combination of two or more elements and sodium is an element with a chemical symbol Na and a charge of +1 and chloride too is an element with a chemical symbol Cl and a charge of -1 so when these two elements are combine it form a chemical solution called Sodium chloride
Answer:- 3.84 grams
Solution:- Volume of the sample is 44.8 mL and the density is 1.03 gram per mL.
From the density and volume we calculate the mass as:
mass = volume*density

= 46.1 g
From given info, potassium bromide solution is 8.34% potassium bromide by mass. It means if we have 100 grams of the solution then 8.34 grams of potassium bromide is present in. We need to calculate how many grams of potassium bromide are present in 46.1 grams of the solution.
The calculations could easily be done using dimensional analysis as:

= 3.84 g KBr
Hence, 3.84 grams of KBr are present in 44.8 mL of the solution.
2 molecules of N2, because the hydrogen is the limiting reactant, leaving there to be more N (4 molecules) so those 4 molecules create 2 N2 molecules.