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n200080 [17]
3 years ago
9

Which atomic particles have no charge? ​

Chemistry
1 answer:
mezya [45]3 years ago
5 0

Answer:

the answer is neutron :)))))))))

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Help Pls thnk you !!!!!!!!!!!!!!!!!!!!!!!!!
uysha [10]
The answer is double displacement is the answer
3 0
3 years ago
A doctor's Order is 0.125 g of ampicillin. The liquid suspension on hand contains 250 mg/s. How many milliliters (mL) of the sus
Molodets [167]

Answer:

c) 2.5 mL

Explanation:

Solution

Doctors order = 0.125g

and

The liquid suspension concentration = 250 mg/5ml

= 0.250g/5ml

Or 0.05g/ml

Amount of ml of suspension required = 0.125g/(0.05g/ml) = 2.5ml

7 0
3 years ago
While in Europe, if you drive 109 km per day, how much money would you spend on gas in one week if gas costs 1.10 euros per lite
MrRissso [65]

Answer:

The amount is x  =  113.3 \  dollars

Explanation:

From the question we are told that

     The  distance traveled per day is  l  =  109\ km =  \frac{109}{1.609}  =  67.74 \  mi

    The  cost of one liter is  c =  1.10 \ euros/liter = 1.10  *  1.26  = 1.36 \ dollars/liter

     The car's  gas mileage is  b =  22.0 \ mi/gal

Generally the amount of distance covered in one week is evaluated as

      z =  67.74 * 7

       z = 474.18 \  mi

The  amount of gas used in one week by the car is mathematically represented as  

       k  = \frac{ z}{ b}

=>    k  = \frac{ 474.18}{ 22}

=>      k  =  22 \ gal

converting to liters

          k =  22 *  3.78541=83.28 \ liters

Thus the amount spent on gas in one week is  

          x =  k *  c

=>      x  =  83.28 *  1.36

=>      x  =  113.3 \  dollars

 

5 0
3 years ago
If a gas is initially at a pressure of 9 atm, a volume of 21 liters, and a temperature of 253 K, and then the pressure is raised
alex41 [277]

Answer:

15.04 mL

Explanation:

Using Ideal gas equation for same mole of gas as

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

Given ,  

V₁ = 21 L

V₂ = ?

P₁ = 9 atm

P₂ = 15 atm

T₁ = 253 K

T₂ = 302 K

Using above equation as:

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

\frac {{9}\times {21}}{253}=\frac {{15}\times {V_2}}{302}

Solving for V₂ , we get:

<u>V₂ = 15.04 mL</u>

3 0
3 years ago
If you had 240 L container at 479 k and 300 kpa, what would the volume be if you changed the conditions to STP
nydimaria [60]

Answer:

The answer to your question is V2 = 434.7 l

Explanation:

Data

Volume 1 = V1 = 240 l                             Volume 2 = ?

Temperature 1 = T1 = 479°K                   Temperature 2 = T2 = 293°K

Pressure 1 = P1 = 300 KPa                      Pressure 2 = P2 = 101.325 Kpa

Process

1.- Use the combined gas law to solve this problem

                P1V1/T1 = P2V2/t2

-Solve for V2

               V2 = P1V1T2 / T1P2

2.- Substitution

                V2 = (300)(240)(293) / (479)(101.325)

3.- Simplification

                V2 = 21096000 / 48534.675

4.- Result

                V2 = 434.7 l

6 0
3 years ago
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