1. Write the word equation for the reaction occurring between lead nitrate and sodium chloride. 2. From your answer in 1 write a
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The question is incomplete, here is the complete question:
A chemist prepares a solution of copper(II) sulfate by measuring out 69.2 g of copper(II) sulfate into a 400. mL volumetric flask and filling the flask to the mark with water.
Calculate the concentration in mol/L of the chemist's copper(II) sulfate solution. Round your answer to 3 significant digits.
<u>Answer:</u> The molarity of copper (II) sulfate solution is 1.08 mol/L
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
We are given:
Given mass of copper (II) sulfate = 69.2 g
Molar mass of copper (II) sulfate = 159.6 g/mol
Volume of solution = 400. mL
Putting values in above equation, we get:
Hence, the molarity of copper (II) sulfate solution is 1.08 mol/L