Answer:
52/ 10 = 5 2/10 or 5 1/5
Step-by-step explanation:
first turn the mixed fractions into improper fraction
13 1/10= 131/10
7 9/10= 79/10
since the two fractions already have a common denominator just subtract
131 - 79 = 52
52/ 10 = 5 2/10 or 5 1/5
Answer:
6 times the value of 3,117 plus 724
Step-by-step explanation:
Hope that helps :)
Recall the definition of the cross product:
i x i = j x j = k x k = 0
i x j = k
j x k = i
k x i = j
The cross product is antisymmetric, or anticommutative, meaning that for any vectors u and v, we have u x v = - (v x u).
It's also distributive, so for any vectors u, v, and w, we have (u + v) x w = (u x w) + (v x w).
Taking all of these properties together, we get
b x a = (6i - j + 2k) x (2i + 2j - 5k)
b x a = 12 (i x i) - 2 (j x i) + 4 (k x i)
............. + 12 (i x j) - 2 (j x j) + 4 (k x j)
............. - 30 (i x k) + 5 (j x k) - 10 (k x k)
b x a = 1 (j x k) + 34 (k x i) + 14 (i x j)
b x a = i + 34j + 14k
I hope this helps you
f (1+1)= f (1)+8
f (2)= 27+8
f (2)=35
f (2+1)= f (2)+8
f (3)= 35+8
f (3)=43
Answer:
C
Step-by-step explanation:
