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bekas [8.4K]
3 years ago
5

[06.01]The same amount of heat is removed from 2 kg of water and from 1 kg of water starting at the same temperature. What will

happen?
Chemistry
1 answer:
liq [111]3 years ago
6 0
<span>Answer: The 1 kg of water will reach the lowest temperature
</span>
Both of the objects is water so their specific heat should be same. The heat removed from the 2kg of water which is 2 times of mass than the 1kg water. Since the heat removed, both of their temperatures will drops. But 2kg water temperature drops will be half of 1kg water.
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In the fermentation of glucose (wine making), 790 mL of CO2 gas was produced at 37 ∘C and 1.00 atm . You may want to reference (
Gennadij [26K]

<u>Answer:</u> The volume of the gas when the pressure and temperature has changed is  0.811 L

<u>Explanation:</u>

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.

The equation follows:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1,V_1\text{ and }T_1 are the initial pressure, volume and temperature of the gas

P_2,V_2\text{ and }T_2 are the final pressure, volume and temperature of the gas

We are given:

Conversion factor used:

1 L = 1000 mL

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P_1=1.00atm=760mmHg\\V_1=790mL=0.790L\\T_1=37^oC=[37+273]K=310K\\P_2=695mmHg\\V_2=?L\\T_2=18^oC=[18+273]K=291K

Putting values in above equation, we get:

\frac{760mmHg\times 0.790L}{310K}=\frac{695mmHg\times V_2}{291K}\\\\V_2=\frac{760\times 0.790\times 291}{310\times 695}=0.811L

Hence, the volume of the gas when the pressure and temperature has changed is 0.811 L

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