1. Compared to oxygen, nitrogen's __________ makes it more difficult for water molecules to the surround nitrogen molecules.
<span>2. The high solubility of sulfur dioxide can be explained by its ____________. </span>
<span>3. Nitric oxide is more soluble than nitrogen and oxygen because of its _______________. </span>
<span>4. Compared to nitrogen, the ___________ of ethylene makes it more soluble in water. </span>
<span>CHOICES are: </span>
<span>a. shorter bond length </span>
<span>b. ability to react with water </span>
<span>c. larger molecular size </span>
<span>d. polarity
answers: </span><span>a, b, d, c.</span><span>
</span>
A useful dilution relationship is (M1V1)=(M2V2) where M is molarity and V is volume in liters.
(6.00M x V1) = (2.00M x .500L) (I assume you mean 2.0M)
V1= (2.00M x .500L)/6.00M
V1= 0.167L
Answer:
The part of the experiment that is set to compare data
Explanation:
The controlled variable is what stays constant throughout an experiment. You use the controlled variable to compare the new data to see what happened during whatever reaction you could say.
Answer:
17 ppm
Explanation:
Paso 1: Información brindada
Masa de soluto: 0.025 g
Volumen de solución: 1.5 L
Paso 2: Convertir la masa de soluto a miligramos
Usaremos el factor de conversión 1 g = 10³ mg.
0.025 g × (10³ mg/1 g) = 25 mg
Paso 3: Calcular las partes por millon (ppm) del soluto
Usaremos la siguiente expresión.
ppm = mg de soluto / litros de solución
ppm = 25 mg / 1.5 L
ppm = 17 mg/L
Answer:
14 OH⁻(aq) + 2 Cr³⁺(aq) = Cr₂O₇²⁻(aq) + 7 H₂O(l) + 6 e⁻
Explanation:
In order to balance a half-reaction we use the ion-electron method.
Step 1: Write the half-reaction
Cr³⁺(aq) = Cr₂O₇²⁻(aq)
Step 2: Perform the mass balance, adding H₂O(l) and OH⁻(aq) where appropriate
14 OH⁻(aq) + 2 Cr³⁺(aq) = Cr₂O₇²⁻(aq) + 7 H₂O(l)
Step 3: Perform the electric balance, adding electrons where appropriate
14 OH⁻(aq) + 2 Cr³⁺(aq) = Cr₂O₇²⁻(aq) + 7 H₂O(l) + 6 e⁻