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Contact [7]
3 years ago
7

Each day tarquin ate 25% of his chocolate.After 4 days he had 1620 chocolate left.How many chocolates did u initially have?​

Mathematics
2 answers:
Leya [2.2K]3 years ago
7 0

Answer:  414720

Step-by-step explanation: Just multiply by 4, 4 times lol

Pani-rosa [81]3 years ago
6 0

Answer:

3240

Step-by-step explanation:

25% of 1620 is 405

Initial chocolate number is multiple 405 by 4 then add into 1620

405 *4 =1620

1620+1620 =3240

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How far can the center of the box be from the end of the table before the board begins to tilt?
Vesnalui [34]

in case of box start being tilt,

box should be half out the table,

<h3>What is COM?</h3>

The Center of Mass of an object or system of objects is a location that is specified in relation to those objects. The Center of Mass of a system is the location where all of its components are on average when they are all weighted in accordance with their masses. The centroid is where basic stiff objects with homogenous density have their centers of mass. Sometimes an object's Center of Mass might not be directly over it. The Center of Mass would be on the Center in the event of a uniform disc, but there would be no material in the case of a ring where the Center of Mass would be on the Center.

The Centre of Mass for intrinsic shapes can be defined as the position where the sum of all of its weighted position vectors of all the parts equals zero.

In this we can use the Center of Mass concept,

As it will leave table when normal is not acting from the table at the center of mass.

So, as in case of box measuring ( x, y, z ) the center of mass from any point of the box is \sqrt{x^{2} +y^{2}+ z^{2}  }

So in case of box start being tilt,

box should be half out the table,

So that COM must be just outside the table

To learn more about Position vector , visit,

brainly.com/question/1563531

#SPJ1

7 0
1 year ago
The line y = 2x-5 cuts the x and y axes at point A and B respectively.
neonofarm [45]

To find the coordinates of points A and B, go to Desmos and graph the given equation.

The word gradient means slope.

The slope is the coefficient of x in the equation. See it?

The gradient is 2.

8 0
3 years ago
Find the equation of the line that passes through the points (3,-2) and (6,-8)
Karolina [17]

Answer:

2x + y = 4

Step-by-step explanation:

The two-point form of the equation of a line is:

y - y_1 = \dfrac{y_2 - y_1}{x_2 - x_1}(x - x_1)

We have:

x1 = 3

y1 = -2

x2 = 6

y2 = -8

Plug in all the values where they belong in the equation above.

y - (-2) = \dfrac{-8 - (-2)}{6 - 3}(x - 3)

Simplify.

y + 2 = \dfrac{-6}{3}(x - 3)

y + 2 = -2(x - 3)

y + 2 = -2x + 6

2x + y = 4

3 0
2 years ago
Respuesta de 17 entre 264. 31
Alexxandr [17]
<span>0.0643184139836

creo que a eso te refieres!!!

hay una paguina de brainly en espanol ahi tambien te pueden ayudar

es:brainly.lat


</span>
4 0
3 years ago
Write a definite integral that represents the area of the region. (Do not evaluate the integral.)
joja [24]

Answer:

\int_{-1}^{1}7(x^{3}-x)\:dx

Step-by-step explanation:

1)  The other curve is y=0 then the common points of both curves are x-intercepts, the roots of y=7(x^{3}-x)

y=7(x^{3}-x)\Rightarrow 7(x^3-x)=0 \Rightarrow 7(x^{3}-x)=7x(x-1)(x-1)\Rightarrow \\S=\left ( 0,0 \right ),\left ( -1,0 \right ),\left ( 1,0 \right )

2). Then those intersection points are the upper and the lower limits. Plugging in to this formula for they belong to the interval [-1,1]:

\int_{a}^{b}|f(x)-g(x)dx

\int_{a}^{b}|f(x)-g(x)dx \Rightarrow \int_{-1}^{1}|7(x^{3}-x)-0|dx \Rightarrow \int_{-1}^{1}7(x^{3}-x)\:dx

 

8 0
3 years ago
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