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3 years ago

During a winter storm 9 inches fell in 12 hours how many inches of snow fell per hour

Mathematics

2 answers:

OlgaM077 [116]3 years ago

6 0

divide total by time:

9 / 12 = 0.75 inches per hour

if you need it as a fraction 0.75 = 3/4

Sladkaya [172]3 years ago

3 0

To find the anwser we have to find the unit rate of snow fall for hour
9/12 = 3/4 so 3/4 inches per hour,

hope this helps!

*miles, and money goes on the bottom when your doing a ratio

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Find the area and circumference of a circle with radius 2 cm use 3.14 for pie do not round answers

Vlad1618 [11]

Answer:

The area is 12.56, and the circumference is 12.56.

Step-by-step explanation:

For the area,

We need to use the formula A=3.14*radius*radius

So we plug it in, and we get 3.14*2*2, which is 12.56 centimeters squared.

For circumference, we need to do,

C = 3.14*diameter

To find the diameter we need to do 2 (radius) x 2 which is 4

Plugging it in that would be 3.14 * 4 which is 12.56

So, in this case, the area is 12.56, and the circumference is also 12.56.

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3 years ago

1+Sin/Cos + Cos/1+Sin = 2Sec

Bond [772]

Step-by-step explanation:

Consider the left-hand side:

$\dfrac{1+\sin{\theta}}{\cos{\theta}} + \dfrac{\cos{\theta}}{1+\sin{\theta}}$

$\:\:\:\:= \dfrac{(1+\sin{\theta})^2 + \cos^2{\theta}}{\cos{\theta}(1+\sin{\theta})}$

$\:\:\:\:=\dfrac{1+2\sin{\theta}+\sin^2{\theta} + \cos^2{\theta}}{\cos{\theta}(1+\sin{\theta})}$

$\:\:\:\:=\dfrac{2+2\sin{\theta}}{\cos{\theta}(1+\sin{\theta})} =\dfrac{2(1+\sin{\theta})}{\cos{\theta}(1+\sin{\theta})}$

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3 years ago

How to factor 6n2 - 6n - 12

alexandr402 [8]

We see that in these 3 terms, 6 is a common factor. So, let's factor out a 6:

$6n^2-6n-12 = 6(n^2-n-2)$

We can set this equal to 0 and factor by using the quadratic formula which is:

$x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

So, let's do just that:

$6(n^2-n-2) = 0$

Note that the 6 goes away if you divide both sides by 6. In this case, a = 1, b = -1, and c = -2. Let's plug that into the quadratic equation:

$\frac{1 \pm \sqrt{(-1)^2-4(1)(-2)} }{2(1)} = \frac{-1 \pm \sqrt{1-(-8)} }{2}$

$\frac{-1 \pm \sqrt{9} }{2} = {1, -2}$

So, we can write this as:

$6n^2 - 6n - 12 = 6(n-1)(n+2)$

Notice that the 6 comes back because it was only temporarily mad. And that the roots have opposite signs in the parentheses because to find the roots, you need to set each parentheses equal to 0 and solve for n. With that in mind, your final answer is 6(n-1)(n+2). Hope I could help you!

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3 years ago

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Ber [7]

Answer:

I believe it would be (1,0)

Step-by-step explanation:

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That being said, C has an x value of 0, and a y value of -3.

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Therefore, the x value would remain unaffected, and the y value becomes 1.

Hope this helps! Keep in mind this is not a 100% definitely correct answer, but from what I remember this would be the new value.

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2 years ago

Mr. Thomas spent $1,600 of his savings on a television set and 2/5 of the remainder on a refrigerator. He had 1/3 of his origina

Katena32 [7]

Answer:

The amount spent on the refrigerator is $ 800 .

Step-by-step explanation: