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AnnZ [28]
3 years ago
9

HELP PLEASE !!!! How many moles of carbon are in one mole of CH4

Chemistry
1 answer:
hodyreva [135]3 years ago
7 0

Answer: 1 Mole or 6.022 X 1023.

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CAN SOMEONE PLEASE HELP ME ASAP PLEASEE ANYBODY LITERALLY ANYONE OUT THERE PLEASE
IgorC [24]

Answer:

Electrons

Explanation:

Atoms can combine together and share electrons between them. Atoms that share electrons are linked to each other in a form, called a molecule that is in a lower energy state than either of the separate atoms alone.

Pls Brainliest! It would mean a lot! ;)

4 0
3 years ago
If one of the impurities in diesel fuel has the formula c2h6s, what products will be formed when it burns? enter a balanced chem
inna [77]
<span>If one of the impurities in diesel fuel has the formula c2h6s, then the products that will form would be carbon dioxide, water and sulfur dioxide. The balanced chemical reaction would be as follows:

</span>C2H6S(l)<span> + 9/2O2(g) = 2CO2(g) + 3H2O(v) + SO2(g)
</span>
Hope this answers the question.
7 0
3 years ago
Read 2 more answers
Give an example of how natural selection could benefit a species. Justify your response in two or more complete sentences.
PolarNik [594]
Natural selection can benefit a species in many ways. One way natural selection benefits a species is by helping a species adapt to constant changing environments and biomes. natural selection can also benefit a species by dying of the weaker links of a species and adapting the mutated species. hope this helped! :)
4 0
3 years ago
The reaction A(B) = 2B(g) has an equilibrium constant of K = 0.045. What is the equilibrium constant for the reaction B(g) =1/2A
Mamont248 [21]

Answer:

The  K_c for the reaction B(g) = \frac{1}{2}A will be 4.69.

Explanation:

The given equation is A(B) = 2B(g)

to evaluate equilibrium constant for B(g) = \frac{1}{2}A

            K_c=[B]^2[A]

                 = 0.045

The reverse will be 2B\leftrightharpoons A

Then,      K_c = \frac{[A]}{[B]^2}

                    =  \frac{1}{0.045}

                    = 22m^{-1}

The equilibrium constant for B(g) = \frac{1}{2}A will be

               K_c = \sqrt{K_c}

                    =\sqrt{22}

                    = 4.69

Therefore, K_c for the reaction B(g) = \frac{1}{2}A will be 4.69.

5 0
3 years ago
Is this the correct answer?
Alona [7]
I believe so, looks like it
8 0
3 years ago
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