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hammer [34]
2 years ago
13

How would you describe the behavior of particles in a solid?

Chemistry
1 answer:
ehidna [41]2 years ago
4 0
A.

Particles within a solid only vibrate in place.
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Attempt 4 A galvanic cell has an X electrode with X 2 plus ions in the left beaker and a Y electrode with Y 2 plus ions in the r
babymother [125]

Answer:

See explaination

Explanation:

Since X is more reactive than Y

=> X is oxidized to X2+ and Y2+ is reduced to Y

Overall cell reaction is:

X(s) + Y2+(aq) => X2+(aq) + Y(s)

please kindly see attachment for further solution.

4 0
3 years ago
How mamy moles of NaCl will be produced from 83.0g of Na, assuming Cl2 is available in excess
Anestetic [448]

Answer:

3.62moles

Explanation:

First let us generate a balanced equation for the reaction

2Na + Cl2 —> 2NaCl

Molar Mass of Na = 23g/mol

Mass of Na from the balanced equation = 2 x 23 = 46g

Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol

Mass of NaCl from the balanced equation = 2 x 58.5 = 117g

From the question,

46g of Na produced 117g of NaCl.

Therefore, 83g of Na will produce = (83 x 117)/46 = 211.11g of NaCl

Converting this mass (211.11g of NaCl) to mole, we obtain:

n = Mass /Molar Mass

n = 211.11/ 58.5

3.62moles

8 0
3 years ago
The first system of classification of organisms was developed by?
Margarita [4]

its the second one alright

5 0
3 years ago
Read 2 more answers
Write the electrons configuration for an atom of an element whose atomic number is 8
Basile [38]
The electron configuration for a atom whose element has a atomic number of 8 (Oxygen) is 2,6
6 0
3 years ago
Equation for questions 1-4:
Karolina [17]

Answer:

5.625 moles of oxygen, O₂.

Explanation:

The balanced equation for the reaction is given below:

4Al + 3O₂ —> 2Al₂O₃

From the balanced equation above,

4 moles of Al reacted with 3 moles of O₂.

Finally, we shall determine the number of mole of O₂ required to react with 7.5 moles of aluminum, Al. This can be obtained as illustrated below:

From the balanced equation above,

4 moles of Al reacted with 3 moles of O₂.

Therefore, 7.5 moles of Al will react with = (7.5 × 3)/4 = 5.625 moles of O₂.

Thus, 5.625 moles of O₂ is needed for the reaction.

3 0
3 years ago
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