How would you describe the behavior of particles in a solid?

Alex dragged a log across the yard in 30 the log weighted 400n she did 900 j of work how much power did I she have

In-s [12.5K]

The power used by Alex to drag the log across the yard is determined as 2,656 W.

The mass of the log is calculated as follows;

W = mg

m = W/g

m = (400)/9.8

m = 40.82 kg

<h3>Velocity of the log</h3>

K.E = ¹/₂mv²

v² = 2K.E/m

v² = (2 x 900)/(40.82)

v² = 44.096

v = 6.64 m/s

<h3>Power used by Alex</h3>

P = Fv

P = 400 x 6.64

P = 2,656 W

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5 0

1 year ago

What does changing densities cause to occur

Dafna1 [17]

Answer:

Explanation:

Please Elaborate

8 0

3 years ago

A voltaic cell consists of a Zn>Zn2+ half-cell and a Ni>Ni2+ half-cell at 25 °C. The initial concentrations of Ni2+ and Zn

nlexa [21]

Answer :

(a) The initial cell potential is, 0.53 V

(b) The cell potential when the concentration of $Ni^{2+}$ has fallen to 0.500 M is, 0.52 V

(c) The concentrations of $Ni^{2+}$ and $Zn^{2+}$ when the cell potential falls to 0.45 V are, 0.01 M and 1.59 M

Explanation :

The values of standard reduction electrode potential of the cell are:

$E^0_{[Ni^{2+}/Ni]}=-0.23V$

$E^0_{[Zn^{2+}/Zn]}=-0.76V$

From this we conclude that, the zinc (Zn) undergoes oxidation by loss of electrons and thus act as anode. Nickel (Ni) undergoes reduction by gain of electrons and thus act as cathode.

The half reaction will be:

Reaction at anode (oxidation) : $Zn\rightarrow Zn^{2+}+2e^-$ $E^0_{[Zn^{2+}/Zn]}=-0.76V$

Reaction at cathode (reduction) : $Ni^{2+}+2e^-\rightarrow Ni$ $E^0_{[Ni^{2+}/Ni]}=-0.23V$

The balanced cell reaction will be,

$Zn(s)+Ni^{2+}(aq)\rightarrow Zn^{2+}(aq)+Ni(s)$

First we have to calculate the standard electrode potential of the cell.

$E^o=E^o_{cathode}-E^o_{anode}$

$E^o=E^o_{[Ni^{2+}/Ni]}-E^o_{[Zn^{2+}/Zn]}$

$E^o=(-0.23V)-(-0.76V)=0.53V$

(a) Now we have to calculate the cell potential.

Using Nernest equation :

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}]}{[Ni^{2+}]}$

where,

n = number of electrons in oxidation-reduction reaction = 2

$E_{cell}$ = emf of the cell = ?

Now put all the given values in the above equation, we get:

$E_{cell}=0.53-\frac{0.0592}{2}\log \frac{(0.100)}{(1.50)}$

$E_{cell}=0.49V$

(b) Now we have to calculate the cell potential when the concentration of $Ni^{2+}$ has fallen to 0.500 M.

New concentration of $Ni^{2+}$ = 1.50 - x = 0.500

x = 1 M

New concentration of $Zn^{2+}$ = 0.100 + x = 0.100 + 1 = 1.1 M

Using Nernest equation :

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}]}{[Ni^{2+}]}$

Now put all the given values in the above equation, we get:

$E_{cell}=0.53-\frac{0.0592}{2}\log \frac{(1.1)}{(0.500)}$

$E_{cell}=0.52V$

(c) Now we have to calculate the concentrations of $Ni^{2+}$ and $Zn^{2+}$ when the cell potential falls to 0.45 V.

Using Nernest equation :

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}+x]}{[Ni^{2+}-x]}$

Now put all the given values in the above equation, we get:

$0.45=0.53-\frac{0.0592}{2}\log \frac{(0.100+x)}{(1.50-x)}$

$x=1.49M$

The concentration of $Ni^{2+}$ = 1.50 - x = 1.50 - 1.49 = 0.01 M

The concentration of $Zn^{2+}$ = 0.100 + x = 0.100 + 1.49 = 1.59 M

5 0

3 years ago

What volume of 0. 250 m sulfuric acid solution would be needed to react completely with 18. 00 ml of 0. 350 m ammonia solution?

PolarNik [594]

The volume of 0. 250 m sulfuric acid solution would be needed to react completely with 18. 00 ml of 0. 350 m ammonia solution is 0.0504 L.

The balance reaction is 2KOH+ $H_{2} SO_{4}$ = $2H_{2} O+K_{2} SO_{4}$

This shows us that we need 2 moles of KOH for each mole of sulfuric acid.

So, we write mathematically 2*(0.018*0.350)=(V*0.250)

V=(2*0.018*0.350)/0.250=0.0504 L

<h3>Sulfuric acid</h3>

With the chemical formula H2SO4, sulfuric acid, also known as sulphuric acid or oil of vitriol, is a mineral acid made up of the elements hydrogen, oxygen, and sulfur. It is a viscous liquid that is miscible with water and is colorless, odorless, and viscous.

Since pure sulfuric acid has a significant affinity for water vapor, it does not naturally occur on Earth; as a result, it is hygroscopic and rapidly collects water vapor from the atmosphere. Due to its potent dehydrating and oxidizing qualities, concentrated sulfuric acid is extremely corrosive to various materials, including rocks and metals. One significant exception is phosphorus pentoxide, which dehydrates sulfuric acid to sulfur trioxide instead of being dehydrated by sulfuric acid.

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6 0

1 year ago

2. If 1.75 L of a gas is at 700. K and is under 250. kPa of pressure, what will the new

Andrews [41]

Answer:

Final volume is 3.50L

Explanation:

It is possible to find volume of a gas using combined gas law:

$\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}$

<em>Where P is pressure, V is volume and T is temperature of 1: initial state and 2: final state</em>

If initial state of the gas is:

1.75L of a gas is at 700K and is under 250kPa of pressure

And final state is:

298K and 53.2kPa.

Replacing:

$\frac{250kPa*1.75L}{700K} =\frac{53.2kPa*V_2}{298K}$

0.625L = 0.1785*V₂

Thus, <em>final volume is 3.50L</em>

3 0

3 years ago