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vlabodo [156]
3 years ago
15

A student transfers a gas at STP from a 11.0 L tank to a 25.0 L tank. If the pressure

Chemistry
2 answers:
Burka [1]3 years ago
8 0

. Consider a sample of oxygen gas at 27° C with a volume of 9.55L at a pressure

mariarad [96]3 years ago
8 0

Answer:620 k

Explanation:

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How many cubic miles are 8.48E+08 gallons of water? The density of water at ambient conditions is 1.000 g/mL.
Inessa05 [86]

The volume of the water in cubic meter is determined as 3.2 x 10⁶ m³ .

<h3>Weight of one gallon of water</h3>

The weight of 1 gal of water is given as 3785 g

Mass of 8.48 x 10⁸ gal = 3785 x 8.48 x 10⁸ = 3.2 x 10¹² g

<h3>Volume of the water in cubic meters</h3>

Volume = mass/density

Volume = 3.2 x 10¹² g/1 gmL

Volume = 3.2 x 10¹² mL x 10⁻⁶ m³/mL = 3.2 x 10⁶ m³

Thus, the volume of the water in cubic meter is determined as 3.2 x 10⁶ m³ .

Learn more about volume here: brainly.com/question/1972490

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7 0
2 years ago
The movement of charged particles cannot pass through an electrolyte to produce an electric current.
Rus_ich [418]

The movement of charged particles cannot pass through an electrolyte to produce an electric current.


True

False


FALSE

5 0
3 years ago
What Most Often Causes The Availability Of Water To Change?
Margaret [11]

Answer:the answer is C

Explanation:

8 0
3 years ago
PLEASEEE HELP ITS DUE SOON!
erastovalidia [21]

Answer:

The correct answer would be C) Support

4 0
3 years ago
The Goodyear blimp contains 5.7 x 10^6 L of helium at 25 degrees Celsius and 1 atm. What is the mass in grams of the helium insi
anygoal [31]

Answer:

1.72x10⁻⁵ g

Explanation:

To solve this problem we use the PV=nRT equation, where:

  • P = 1 atm
  • V = 5.7x10⁶ L
  • n = ?
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • T = 25 °C ⇒ (25+273.16) = 298.16 K

And we <u>solve for n</u>:

  • 1 atm * 5.7x10⁶ L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K
  • n = 4.29x10⁻⁶ mol

Finally we <u>convert moles of helium to grams</u>, using its <em>molar mass</em>:

  • 4.29x10⁻⁶ mol * 4 g/mol = 1.72x10⁻⁵ g

8 0
3 years ago
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