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Fynjy0 [20]
3 years ago
10

The balanced equation below represents the reaction between a 5.0 gram sample of zinc metal and 0.5 M of hydrochloric acid. The

reaction takes place in an open test tube at 298K and 1 atm in a laboratory activity ​

Chemistry
1 answer:
mezya [45]3 years ago
5 0

Answer:

1) Increasing the concentration of HCl [HCl] will increase the reaction rate.

2) The potential energy diagram is shown in the attached image.

3) Because of it is an irreversible reaction that goes to the forward direction . The reaction takes place till HCl dissolves Zn completely.

Explanation:

<em>Q1: State one change in reaction conditions, other than adding catalyst, that will increase the rate of the reaction.</em>

  • The rate of the reaction, dissolving Zn in HCl, depends on the concentration of HCl.

Rate = k[HCl]².

<em>Rate ∝ [HCl]².</em>

  • The rate is directly proportional to the concentration of HCl raised to the power 2,

<em>So, increasing the concentration of HCl [HCl] will increase the reaction rate.</em>

<em></em>

<em>Q2: Draw a potential energy diagram for this reaction.</em>

<em></em>

  • Since the reaction releases energy that appears in the products side. So, the reaction is an exothermic reaction.

In an exothermic reaction, the energy of the reactants is higher than that of the products.

<em>The potential energy diagram is shown in the attached image.</em>

<em></em>

<em>Q3: Explain why this reaction will not reach equilibrium.</em>

Because of it is an irreversible reaction that goes to the forward direction . The reaction takes place till HCl dissolves Zn completely.

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Answer:

Explanation:

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Showing results for V = d/t a = (V - Vil/t Vaverage = (V+ + V)/2 with constant acceleration d = Vit + 2 at? Vi = (V2 + 2ad)1/2 =VV2 + 2ad A stick figure throws a ball straight up into the air at 5 m/s. g = "-9.81" m/s2 1. How long does it take to reach the top? 2. How long does it take to come back to the level of release? 3. If the hand is 1 m from the ground, how long will it take to hit the ground if the ball is not caught? 4. How high is the ball at the top from the ground? 5. What is the displacement of the ball, if it is caught on return? 6. What is the displacement of the ball to the top from release? 7. What is final velocity when you catch the ball on return to your hand? 8. What is the final velocity as it hits the ground? 9. What is the velocity at the top?

Search instead for V = d/t a = (V - Vil/t Vaverage = (V+ + V)/2 with constant acceleration d = Vit + 2 at? Vi = (V2 + 2ad)1/2 =VV2 + 2ad A stick figure throws a ball straight up into the air at 5 m/s. g = -9.81 m/s2 1. How long does it take to reach the top? 2. How long does it take to come back to the level of release? 3. If the hand is 1 m from the ground, how long will it take to hit the ground if the ball is not caught? 4. How high is the ball at the top from the ground? 5. What is the displacement of the ball, if it is caught on return? 6. What is the displacement of the ball to the top from release? 7. What is final velocity when you catch the ball on return to your hand? 8. What is the final velocity as it hits the ground? 9. What is the velocity at the top?

7 0
3 years ago
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Answer: Option (A) is the correct answer.

Explanation:

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This energy travels through one molecule of water to another molecule of water by the process of convection.

Thus, we can conclude that when energy is transferred from the air to the water, then it travels through the water.

3 0
4 years ago
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