BD=10 because it is symmetrical to AD.
Answer:
![E(X)= n \int_{0}^1 x^n dx = n [\frac{1}{n+1}- \frac{0}{n+1}]=\frac{n}{n+1}](https://tex.z-dn.net/?f=E%28X%29%3D%20n%20%5Cint_%7B0%7D%5E1%20x%5En%20dx%20%3D%20n%20%5B%5Cfrac%7B1%7D%7Bn%2B1%7D-%20%5Cfrac%7B0%7D%7Bn%2B1%7D%5D%3D%5Cfrac%7Bn%7D%7Bn%2B1%7D)
Step-by-step explanation:
A uniform distribution, "sometimes also known as a rectangular distribution, is a distribution that has constant probability".
We need to take in count that our random variable just take values between 0 and 1 since is uniform distribution (0,1). The maximum of the finite set of elements in (0,1) needs to be present in (0,1).
If we select a value
we want this:

And we can express this like that:
for each possible i
We assume that the random variable
are independent and
from the definition of an uniform random variable between 0 and 1. So we can find the cumulative distribution like this:

And then cumulative distribution would be expressed like this:



For each value
we can find the dendity function like this:

So then we have the pdf defined, and given by:
and 0 for other case
And now we can find the expected value for the random variable X like this:

![E(X)= n \int_{0}^1 x^n dx = n [\frac{1}{n+1}- \frac{0}{n+1}]=\frac{n}{n+1}](https://tex.z-dn.net/?f=E%28X%29%3D%20n%20%5Cint_%7B0%7D%5E1%20x%5En%20dx%20%3D%20n%20%5B%5Cfrac%7B1%7D%7Bn%2B1%7D-%20%5Cfrac%7B0%7D%7Bn%2B1%7D%5D%3D%5Cfrac%7Bn%7D%7Bn%2B1%7D)
Hello!
<em>According to the diagram, your answer is</em> <em>D.) Some Elephants have tusks</em>
If the entire circle labeled "Elephants" was inside the circle labeled "Animals With Tusks," it would be A, but that is not the case. only part of it is inside. so D is the correct answer.
I hope this helps, and have a nice day!
Answer:

Step-by-step explanation:

Answer:
12 and 15 or
12 and 18 or
15 or 18
Step-by-step explanation:
The two numbers have to both be divisible by 3, since their greatest common factor is 3. This only leaves..
12, 15, or 18 (no other numbers between 10 and 20 are divisible by 3)
The factors of 12 are: 2, 3, 4, 6, and 12
The factors of 15 are: 3, 5, and 15
The factors of 18 are: 2, 3, 6, 9, and 18
All three numbers have 3 as a greatest common factor, so we have 3 pairs of numbers they could be...
12 and 15 or
12 and 18 or
15 or 18