The genes for miniature wings (m) and garnet eyes (g) are approximately 8 map units apart on chromosome 1 in Drosophila. Phenoty
pically wild-type females (m + g / mg +) were mated to miniature-winged males with garnet eyes. Which of the following phenotypic classes reflect offspring that were generated as a result of a crossover event?
1. garnet eyes
2. wild type
3 .miniature wings
4 .miniature wings, garnet eyes
Two types of posterity can be created subsequent to mating: parental and recombinant. Recombinants are created because of the traverse of non-sister chromatids at the hour of gamete arrangement. Here, mating happens between m+g/mg+ female and mg/mg male so the posterity would be separated as follows:
m+g/mg : Parental
mg+/mg : Parental
m+g+/mg : Recombinant
mg/mg : Recombinant
m+g+/mg (wild sort) and mg/mg (smaller than usual wings, garnet eyes) are the recombinants thus they were created because of the hybrid occasion.
Hence,the right answer is option 2 & 4 "wild type and miniature wings,garnet eyes"
Because during digestion, blood is needed to execute the process. Swimming also requires blood so it takes the blood that was initially being used for digestion away.
