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Serga [27]
3 years ago
15

The genes for miniature wings (m) and garnet eyes (g) are approximately 8 map units apart on chromosome 1 in Drosophila. Phenoty

pically wild-type females (m + g / mg +) were mated to miniature-winged males with garnet eyes.
Which of the following phenotypic classes reflect offspring that were generated as a result of a crossover event?
1. garnet eyes
2. wild type
3 .miniature wings
4 .miniature wings, garnet eyes
Biology
1 answer:
Luden [163]3 years ago
7 0
<h2>Answer is option " 2 & 4"</h2>

Explanation:

  • Two types of posterity can be created subsequent to mating: parental and recombinant. Recombinants are created because of the traverse of non-sister chromatids at the hour of gamete arrangement. Here, mating happens between m+g/mg+ female and mg/mg male so the posterity would be separated as follows:  
  • m+g/mg : Parental  
  • mg+/mg : Parental  
  • m+g+/mg : Recombinant  
  • mg/mg : Recombinant  
  • m+g+/mg (wild sort) and mg/mg (smaller than usual wings, garnet eyes) are the recombinants thus they were created because of the hybrid occasion.
  • Hence,the right answer is option 2 & 4 "wild type and miniature wings,garnet eyes"

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