Name the ester that is formed when pentanoic acid reacts with isopropanol.a.isopropyl pentanoateb.isopropyl pentanec.pentanoate
isopropyld.isopropyl pentanoic acid
2 answers:
Answer:
a. Isopropyl pentanoate.
Explanation:
Hello,
In this case, such esterification is:
Wherein the first reactant is the pentanoic acid, the second one the isopropanol and the first product is the result, which is a. isopropyl pentanoate. This is because the isopropyl get separated from the hydroxile and bonds with the carboxile group of the pentanoic acid by also releasing water as the byproduct.
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The energy absorbed by the system before the reaction start has been 752 kJ/mol.
The bond energy has been defined as the energy possessed by the bond that has been converted into the heat energy and utilized in the reaction.
The energy has been conserved in a chemical reaction. Thus, the energy absorbed by the reactant in the reaction has been the difference in the energy of the reactant and product.
<h3>Computation for the energy absorbed</h3><h3 />The given reaction has been:
The bond energy of the reactant has been:
H-H bond energy = 432 kJ/mol
2 C=O bond energy= 799 kJ/mol
The total energy of the reactant has been 432 kJ/mol + 799 kJ/mol
The total energy of the reactant has been 1231 kJ/mol
The bond energy of the product has been:
C-O bonds = 358 kJ/mol
C=O bonds = 745 kJ/mol
1 C-H bond = 413 kJ/mol
1 O-H bond = 467 kJ/mol
The total energy of the product has been 358 + 745 + 413 + 467 kJ/mol
The total energy of the product has been 1,983 kJ/mol
According to the law of conservation of energy:
Substituting the values for energy absorbed:
The energy absorbed by the system before the reaction start has been 752 kJ/mol.
Learn more about bond energy, here: