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Levart [38]
4 years ago
8

Lithium hydroxide is classified as an A. Arrhenius base B. Arrhenius acid C. Alcohol D. Aldehyde

Chemistry
1 answer:
k0ka [10]4 years ago
7 0
Lithium hydroxide is classified as an annhenius base since it dissociates into lithium cations and hydroxide an ions and Arrhenius bases are defined as a substance that dissociated into hydroxide anions (as well as cations) when in solution. I hope this helps. Let me know if anything is unclear.
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When Johann Schweigger invented the first galvanometer, what did he recognize could be used to measure current:"
lukranit [14]
He improved and followed from the works of Luigi Galvani, which used a 'frog galvanoscope' as a prototype of measuring current. He recognized that a compass could actually measure current, given that it is placed near coil of wire. 
6 0
3 years ago
Frieda makes a pyramid of oranges for a display at the grocery store. A few minutes later, Corwin bumps into the display and the
olga_2 [115]

Answer:

Melting!!!

Explanation:

Melting is just like this. When a solid's atoms are in place, they are like the oranges before - Carefully organized, not moving much, in a structure.

When a solid starts melting into a liquid, the molecules start bouncing off each other, collapsing. :)

So, the answer is <u>Melting!</u>

7 0
3 years ago
Read 2 more answers
A sample of carbon dioxide occupies a volume of 2.50L liters at 300kPa pressure and a temperature 273K. What pressure would the
Drupady [299]

Answer:

The answer to your question is:    P2 = 846 kPa

Explanation:

Data

V1 = 2.5 l

P1 = 300 kPa

T1 = 273 °K

P2 = ?

V2 = 1 l

T2 = 308°K

Formula

             \frac{P1V1}{T1}  = \frac{P2V2}{T2}

             P2 = \frac{P1V1T2}{T1V2} \\

             P2 = \frac{(300)(2.5)(308)}{(273)(1)} \\

            P2 = \frac{231000}{273} \\

            P2 = 846 kPa

5 0
3 years ago
Which of the following is an example of a behavioral trait that
masya89 [10]

Answer:

The answer is option A

Colorful feathers

Hope this helps you

3 0
3 years ago
A total of 620 C of charge passes through a flashlight in 0.510 h. What is the average current in milliamperes?
aniked [119]

Explanation:

The given data is as follows.

               Q = 620 C,         t = 0.510 hour

First, we will convert hours into seconds. Since, there are 3600 seconds present in 1 hour. Hence, number of seconds present in 0.510 hour are as follows.

                   0.510 hr \times \frac{3600 sec}{1 hr}

                     = 1836 sec

Therefore, we will calculate the average current as follows.

                      I = \frac{Q}{t}

                        = \frac{620 C}{1836 sec}

                        = 0.337 C/sec

It is known that,

                      1 C/sec = 1000 mA

So,             0.337 C/sec \times \frac{1000 mA}{1 C/s}

                    = 337 mA

Thus, we can conclude that the average current in milliamperes is 337 mA.

4 0
3 years ago
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