Answer:
Make the surfaces little more smoother. ...
Lubrication is another way to make a surface smoother. ...
Make the object more streamlined. ...
Reduce the Normal force acting between the surfaces in contact. ...
Reduce the contact between the surfaces, so that less number of bonds will be formed.
Explanation:
A wave on a string is described is given by :
![D(x,t)=2\ cm\ sin[(12.57\ rad/m)-(638\ rad/s)t]](https://tex.z-dn.net/?f=D%28x%2Ct%29%3D2%5C%20cm%5C%20sin%5B%2812.57%5C%20rad%2Fm%29-%28638%5C%20rad%2Fs%29t%5D)
The linear density of the string is 5 g/m.
Where
x is in meters and t is in seconds
The general equation of a wave is given by :
(2) The speed of the wave in terms of tension is given by :

Also, 
So, 


T = 12.88 N
(3) The maximum displacement of a point on the string is equal to the amplitude of the wave. So, the maximum displacement is 2 cm.
(4) The maximum speed of a point on the string is given by :


v = 12.76 m/s
Hence, this is the required solution.
Newton's second law of motion involves the effect of force acting on a mass.
It has to be understood that this actually means the combination of any and
all individual forces acting on it, with their individual strengths and directions
all added together.
When all the individual forces acting on an object add up to zero, then the
whole group of forces is said to be 'balanced'.
When all the individual forces acting on an object don't add up to zero, then
the whole group of forces is said to be 'unbalanced'.
Notice that there's no such thing as 'a balanced force' or 'an unbalanced force'.
It's a <u>group</u> of two or more forces that's balanced or unbalanced.
Answer:
The acceleration is
and the distance covered is 97.17 m.
Explanation:
Given that,
Initial speed of an automobile, u = 60 km/hr = 16.67 m/s
Final speed of an automobile, v = 80 km/hr = 22.2 m/s
Time, t = 5 s
We need to find the acceleration of the car and the distance traveled in this 5 sec interval. Let a is the acceleration. Using the definition of acceleration as :

Let d is the distance covered. Using the third equation of motion to find it as follows :

So, the acceleration is
and the distance covered is 97.17 m.