A force acts on a body of mass 13 kg initially at rest. The force
1 answer:
Answer:
Force that acted on the body was F = 13 N
Explanation:
If once accelerated, the body covers 60 meters in 6 seconds, then its velocity is 60/6 m/s = 10 m/s
When the force was acting (for 10 seconds) the object accelerated from rest (initial velocity vi = 0) to 10 m/s (its final velocity). therefore we can use the kinematic equation for the velocity in an accelerated motion given by:
which in our case becomes;
and we can solve for the acceleration as:
a = 10/10 m/s^2 = 1 m/s^2
Therefore the force acting on the body, based on Newton's 2nd Law expression: F = m * a is:
F = 13 kg * 1 m/s^2 = 13 N
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Answer:
the mass of steam at 100°C must be mixed is 150 g
Explanation:
given information:
ice's mass, = 490 g = 0.49 kg
steam temperature, T = 100°C
liquid water temperature, T = 89.0°C
specific heat of water, = 4186 J/kg.K = 4.186 kJ/kg.K
latent heat of fusion, = 333 kJ/kg
latent heat of vaporization, = 2256 kJ/kg
first, we calculate the heat of melted ice to water
Q₁ =
where
Q = heat
= mass of the ice
= latent heat of fusion
thus,
Q₁ =
= 0.49 x 333
= 163.17 kJ
then, the heat needed to increase the temperature of water to 89.0°C
Q₂ =
(89 - 0), the temperature of ice is 0°C
= specific heat of water
so,
Q₂ =
(89 - 0)
= 0.49 x 4.186 x 89
= 182.55 kJ
so, the heat absorbed by the ice is
Q = Q₁ + Q₂
= 163.17 + 182.55
= 345.72 kJ
the temperature of the steam is 100°C, so the mass of the steam is
Q = +
(100 - 89)
Q = (
+
(11))
= Q/ [
+
(11)]
= 345.72/ [2256 + (4.186 x 11)]
= 0.15 kg
= 150 g