Answer:
Resistance can increase relative to Temperature, Nature of Material, Length of Conductor or wire.,and Cross-section area.
Explanation:
<span>Total KE = KE (rotational) + KE (translational)
Moment of inertia of sphere is I = (2/5)mr^2
So KE (rotational) = (1/2) x I x w^2 = (1/2) x (2/5)mr^2 x w^2 = (1/5) x m x r^2 x w^2
KE (translational) = (1/2) x m x v^2 = (1/2) x m x (rw)^2 = (1/2) x m x r^2 x w^2
Hence KE = (1/5) x m x r^2 x w^2 + (1/2) x m x r^2 x w^2 = m x r^2 x w^2 ((1/5) + (1/2))
KE = (7/10) m x r^2 x w^2
Calculating the fraction of rotational kinetic energy to total kinetic energy,
= rotational kinetic energy / total kinetic energy
= (1/5) x m x r^2 x w^2 / (7/10) m x r^2 x w^2 = (1/5) / (7/10) = 2 / 7
The answer is 2 / 7</span>
A = dv/dt = ak
ak = ( 0.0 m/s - 9.0 m/s ) / ( 3 s )
3m/s^2
a star that suddenly increases greatly in brightness because of a catastrophic explosion that ejects most of its mass.
The magnitude of static friction is
<em>f</em> = <em>mv</em> ²/<em>r</em>
(i.e. the net force acting on the car parallel to the road points toward the center of the curve)
while the net vertical force must be
∑ <em>F</em> = <em>n</em> - <em>mg</em> = 0
because the car is otherwise in equilibrium. Then
==> <em>n</em> = <em>mg</em>
==> <em>f</em> = <em>µn</em> = <em>µmg</em> = <em>mv</em> ²/<em>r</em>
==> <em>µ</em> = <em>v</em> ²/(<em>rg</em>)
We have
<em>v</em> = 101 km/h ≈ 28.1 m/s
<em>r</em> = 110 m
<em>g</em> = 9.80 m/s²
so that
<em>µ</em> = (28.1 m/s)² / ((110 m) <em>g</em>) ≈ 0.730
