The answer to your Question is E
Answer:
1) HIGH IMPULSE, SHORT INSTANT
2) SMALL IMPULSE, MORE INSTANT OF TIME
more
Explanation:
Let's propose the solution of this exercise, let's use the relationship between momentum and momentum
I = Δp
F t = m v_f - m v₀
indicates that the carriage stops v_f = 0
F t = - m v₀
Therefore, if the impact time decreases, the force must increase and therefore the damages also
Car A collides with a concrete wall that is rigid, therefore the collision occurs in a very short time, car B collides with area, so the collision time is extended, now we can complete the sentences
1) Stunt Car A experiences a _HIGH IMPULSE_ over a SHORT INSTANT__ of time.
2)Stunt Car B experiences a _SMALL IMPULSE_____ over a _MORE INSTANT__ of time.
3) Because of the force experienced by Stunt Car A, it will sustain __MORE____ damage than Stunt Car B.a
3) more
Answer:
hence the relative intensity is 3.0279 ×
Explanation:
Given data
wavelength 755.0 nm = 755 × m
width d = 2.20 µm = 2.20× m
screen distance D = 26.5 cm
I/Imax Yn = 13.0 cm
to find out
the relative intensity
solution
we know that
tanθ = Yn / D
here Yn is the distance from central maximum and D is here distance from screen put all these value
tanθ = 13 / 26.5
θ = 26.13 degree
so
relative intensity of light will be here
I/ Imax = (sinФ/Ф)² ................1
here Ф is angle that is
Ф = πdsinθ / wavelength
Ф = π(2.20×)sin26.13 / ( 755 ×)
Ф = 7.689
so we put Ф = 7.689 in equation 1
I/ Imax = (sinФ/Ф)²
I/ Imax = (sin7.689/7.689)²
I/ Imax = 3.0279 ×
hence the relative intensity is 3.0279 ×
The correct answer is<span> number of oscillations in a given period of time
This is measured in what is called the Hertz measurement and the period of time is usually taken to be per second.</span>
<u>Answer:</u>
Plane is 1035.76 miles far away from the starting point.
<u>Explanation:</u>
First the plane flies 1.5 hours at 120 mph on a bearing of 10 degrees then it turns and flies 8.5 hours at the same speed on a bearing of 100 degrees.
So angle between the displacements = 100-10 = 90 degrees
Initial displacement = 1.5 *120 = 180 miles
Second displacement = 8.5*120 = 1020 miles
These two displacements are at 90 degrees, so final displacement =
So plane is 1035.76 miles far away from the starting point.