Answer:
72.5
Step-by-step explanation:
580-25% is 435 so if yu need help you just inbox me ok and answer back to this txt
keeping in mind that complex roots never come alone, their sister is always with them, the conjugate, so if we know that "i" or namely "0 + i" is there, her sister the conjugate "0 +i" must also be there too, so let's take a peek
![\begin{cases} x=-5\implies &x+5=0\\ x=0+i\implies &x-i=0\\ x=0-i\implies &x+i=0 \end{cases}\implies \underline{a(x+5)(x-i)(x+i)=\stackrel{0}{y}} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7D%20x%3D-5%5Cimplies%20%26x%2B5%3D0%5C%5C%20x%3D0%2Bi%5Cimplies%20%26x-i%3D0%5C%5C%20x%3D0-i%5Cimplies%20%26x%2Bi%3D0%20%5Cend%7Bcases%7D%5Cimplies%20%5Cunderline%7Ba%28x%2B5%29%28x-i%29%28x%2Bi%29%3D%5Cstackrel%7B0%7D%7By%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\underset{\textit{difference of squares}}{(x-i)(x+i)}\implies [x^2-i^2]\implies [x^2-(-1)]\implies (x^2+1) \\\\[-0.35em] ~\dotfill\\\\ \underline{a(x+5)(x^2+1)=y}~\hfill \stackrel{\textit{we also know that}}{f(\stackrel{x}{-3})=60}~\hfill a[(-3)+5][(-3)^2+1]=60 \\\\\\ a(2)(10)=60\implies 20a=60\implies a=\cfrac{60}{20}\implies a=3 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \underline{3(x+5)(x^2+1)=y}~\hfill](https://tex.z-dn.net/?f=%5Cunderset%7B%5Ctextit%7Bdifference%20of%20squares%7D%7D%7B%28x-i%29%28x%2Bi%29%7D%5Cimplies%20%5Bx%5E2-i%5E2%5D%5Cimplies%20%5Bx%5E2-%28-1%29%5D%5Cimplies%20%28x%5E2%2B1%29%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cunderline%7Ba%28x%2B5%29%28x%5E2%2B1%29%3Dy%7D~%5Chfill%20%5Cstackrel%7B%5Ctextit%7Bwe%20also%20know%20that%7D%7D%7Bf%28%5Cstackrel%7Bx%7D%7B-3%7D%29%3D60%7D~%5Chfill%20a%5B%28-3%29%2B5%5D%5B%28-3%29%5E2%2B1%5D%3D60%20%5C%5C%5C%5C%5C%5C%20a%282%29%2810%29%3D60%5Cimplies%2020a%3D60%5Cimplies%20a%3D%5Ccfrac%7B60%7D%7B20%7D%5Cimplies%20a%3D3%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20%5Cunderline%7B3%28x%2B5%29%28x%5E2%2B1%29%3Dy%7D~%5Chfill)
Check the picture below.
Answer:
xxxxxxxxxxxxxx
Step-by-step explanation:
xxxxxxxxxxxxxxxxxxxx