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DaniilM [7]
3 years ago
5

a cold glass of water is set outside on a hot day and water droplets develop on the outside of the glass describe whats happenin

g
Chemistry
2 answers:
maxonik [38]3 years ago
8 0
The water drops on the outside of the cup come from water that's already in the air. Water can be solid (ice) liquid, or gas. As you increase the temperature, ice melts into water. Then as you increase the temperature more water, and if you cool water enough you get ice. When we think of water as a gas we normally think of steam, which is very hot, but it can also be a gas a normal temperatures. There's always some amount of water as a gas just hanging out in the air, along with nitrogen and oxygen. (When people talk about humidity, they're talking about the amount of water vapor in the air). So if you put a cold cup down on a table, the water vapor in the air that comes in contact with the cup gets cold and will turn into water. This process is called condensation.
notsponge [240]3 years ago
4 0
It is basically condensation   
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A sample of calcium phosphate was found to have a mass of 125.3 g. How many molecules were contained in the sample?
Viktor [21]

The answer for the following problem is mentioned below.

  • <u><em>Therefore number of molecules(N) present in the calcium phosphate sample are  19.3 × 10^23 molecules.</em></u>

Explanation:

Given:

mass of calcium phosphate (Ca_{3}(PO_{4} )_{2} ) = 125.3 grams

We know;

molar mass of calcium phosphate  (Ca_{3}(PO_{4} )_{2} ) = (40×3) + 3 (31 +(4×16))

molar mass of calcium phosphate  (Ca_{3}(PO_{4} )_{2} ) = 120 + 3(95)

molar mass of calcium phosphate  (Ca_{3}(PO_{4} )_{2} )  = 120 +285 = 405 grams

<em>We also know;</em>

No of molecules at STP conditions(N_{A}) = 6.023 × 10^23 molecules

To solve:

no of molecules present in the sample(N)

We know;

\frac{m}{M} =\frac{N} }{}N÷N_{A}

\frac{405}{125.3} =\frac{N}{6.023*10^23}

N =(405×6.023 × 10^23) ÷ 125.3

N = 19.3 × 10^23 molecules

<u><em>Therefore number of molecules(N) present in the calcium phosphate sample are  19.3 × 10^23 molecules</em></u>

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Answer:

hola soy jess, tu respuesta esta aqui

¿cuantos moles de CO2 se requiere para reaccionar 2 moles de Ba(OH)2

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1molBa(OH)

2

1molCO

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= 2 moles CO₂

Explanation:

espero que pueda ayudarte

hermana/hermano

lo que

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