Answer:
A. 2 bonds
Explanation:
If you see a charch of ci20 it would easily show the answer.
Answer:
A) The effect on the net reaction catalyzed by glyceraldehyde is that
The 1-arsen0, 3-phosphoglycerate will decompose without enzymes hence no ATP will be formed in the reaction ( phosphoglycerate Kinase )
B) There will be no conversion of ADP to ATP from the conversion of glucose to pyruvate hence No balanced overall equation can be derived
C ) Arsenate is very toxic to most organisms and it is used mostly regarded as poisons during the formation of glycolysis, it forms 1-arsen0, 3-phosphoglycerate which hinders the formation of ATP because it is unstable and will hydrolyze quickly, this will also lead to the reduction in oxygen in cells thereby leading to the death of cells
Explanation:
A) The effect on the net reaction catalyzed by glyceraldehyde is that
The 1-arsen0, 3-phosphoglycerate will decompose without enzymes hence no ATP will be formed in the reaction ( phosphoglycerate Kinase )
B) There will be no conversion of ADP to ATP from the conversion of glucose to pyruvate hence No balanced overall equation can be derived
C ) Arsenate is very toxic to most organisms and it is mostly regarded as poisons during the formation of glycolysis, it forms 1-arsen0, 3-phosphoglycerate which hinders the formation of ATP because it is unstable and will hydrolyze quickly, this will also lead to the reduction in oxygen in cells thereby leading to the death of cells
Answer:
Mass of oxygen in glucose = 29.3g
Explanation:
Mass of glucose given is 55grams.
We are to find the mass of oxygen in this compound.
In the compound we have 6 atoms of oxygen.
Solution
To find the mass of oxygen in glucose, we calculate the formula mass of glucose. We now divide the formula mass of the oxygen atom with that of the glucose and multiply by the given mass to find the unkown mass.
Atomic mass of C = 12g
H = 1g
O = 16g
Formula mass of C₆H₁₂O₆ = {(12x6) + (1x12) + (16x6)} = 180
Mass of O in glucose = 
x 55
= 
x 55
= 0.53 x 55
Mass of oxygen in glucose = 29.3g
Explanation:
The given data is as follows.
= 10 mM = 
M
= 750 ml, 
= 5 ml
= ?
Therefore, calculate the molarity of given NaCl stock as follows.
= 1.5 M
Thus, we can conclude that molarity of given NaCl stock is 1.5 M.
