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3 years ago

6. Barium sulfate and and sodium sulfate react in a double displacement reaction. If the

Chemistry

1 answer:

azamat3 years ago

6 0

Answer:

6) For 0.04392 moles BaSO4 we need 0.02196 moles Na2SO4

To produce 0.02196 moles Ba2SO4 and 0.04392 moles Na2SO4

7) For 16.08 moles LiOH we'll have 8.04 moles H2SO4 produced.

We need 8.04 moles Li2SO4 and 8.04 moles H2O

8) For 0.0206 moles silvernitrate we'll hace 0.0206 moles silver

9) For 0.014 moles of Cu we'll have 0.014 moles Cu(NO3)2

Explanation:

6. Barium sulfate and and sodium sulfate react in a double displacement reaction. If the reaction starts with 10.25 grams of barium sulfate what are the products and how many moles of each product is produced?

Step 1: Data given

Mass of BaSO4 = 10.25 grams

Molar mass = 233.38 g/mol

Step 2: The balanced equation

2BaSO4 + Na2SO4 → Ba2SO4 + 2NaSO4

Step 3: Calcuate moles BaSO4

Moles BaSO4 = 10.25 grams / 233.38 g/mol

Moles BaSO4 = 0.04392 moles BaSO4

Step 4: Calculate moles

For 2 moles BaSO4 we need 1 mol Na2SO4 to produce 1 mol Ba2SO4 and 2 moles NaSO4

For 0.04392 moles BaSO4 we need 0.04392/2 = 0.02196 moles Na2SO4

To produce 0.02196 moles Ba2SO4 and 0.04392 moles Na2SO4

7. Calculate the moles of Li2SO4that would be needed to produce 385 g of LiOH.

Step 1: Data given

Mass of LiOH = 385 grams

Molar mass of LiOH = 23.95 g/mol

Step 2: The balanced equation

Li2SO4 + 2H2O → 2LiOH + H2SO4

Step 3: Calculate moles LiOH

Moles LiOH = 385.0 grams / 23.95 g/mol

Moles LiOH = 16.08 moles LiOH

Step 4: Calculate moles

For 1 mol Li2SO4 we need 2 moles H2O to produce 2 moles LiOH and 1 mol H2SO4

For 16.08 moles LiOH we'll have 8.04 moles H2SO4 produced.

We need 8.04 moles Li2SO4 and 8.04 moles H2O

8. Silver nitrate reacts with copper in a single displacement reaction. To produce copper (1) nitrate and silver. If 3.50 g of silver nitrate are reacted with excess copper. How many mole of silver would be produced?

Step 1: Data given

Mass of AgNO3 = 3.50 grams

Molar mass of AgNO3 = 169.87 g/mol

Step 2: The balanced equation

Cu + 2AgNO3 → Cu(NO3)2 + 2Ag

Step 3: Calculate moles AgNO3

Moles AgNO3 = 3.50 grams / 169.87 g/mol

Moles AgNO3 = 0.0206 moles

Step 4: Calculate moles of Ag

For 1 mol copper, we need 2 moles of silvernitrate to produce 1 mol of coppernitrate and 2 moles of silver

For 0.0206 moles silvernitrate we'll hace 0.0206 moles silver

9. (Use the chemical equation from above) How many moles of copper (1) nitrate ]can be produced with and 0.89 grams of copper metal?

Step 1: Data given

Mass of Cu = 0.89 grams

Molar mass of Cu = 63.55 g/mol

Step 2: The balanced equation

Cu + 2AgNO3 → Cu(NO3)2 + 2Ag

Step 3: Calculate moles Cu

Moles Cu =0.89 grams / 63.55 g/mol

Moles Cu = 0.014 moles

Step 4: Calculate moles of Coppernitrate

For 1 mol copper, we need 2 moles of silvernitrate to produce 1 mol of coppernitrate and 2 moles of silver

For 0.014 moles of Cu we'll have 0.014 moles Cu(NO3)2

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Which chemical equation represents a decomposition reaction?

MrMuchimi

Decomposition reaction D. 2H20⇒ 2H2 + O2

<h3>Further explanation </h3>

Every chemical reaction involves a compound consisting of reactants and products

Reactants are compounds that react and form new compounds called products

There are several forms of reactions that can occur, including single replacement, double replacement, synthesis, decomposition, etc.

A. 2C2H6 + 702 ⇒ 4CO2 + 6H20

Combustion : reaction of Hydrocarbon and Oxygen

B. AgNO3 + LiCl → AgCl + LINO3

Double replacement : there is an ion exchange between two ion compounds in the reactant to form two new ion compounds in the product

C. Ca + MgS → CaS + Mg

Single replacement :one element replaces the other elements of a compound to produce new elements and compounds

D. 2H20⇒ 2H2 + O2

Decomposition : One compound breaks down into 2 components

8 0

3 years ago

Example: Make 100 mL 0.05 M NaOH from a 1.5 M solution.<br>0.05 * 100 = 1.5 * ?

____ [38]

Answer:

3.33

Explanation:

M= 0.05*100/1.5= 3.33

4 0

3 years ago

A redox reaction can also be a?

AveGali [126]

Losing eltron is the answer

7 0

3 years ago

A compound is 80.0% carbon and 20.0% hydrogen by mass. assume you have a 100.-g sample of this compound. the molar mass of the c

ch4aika [34]

Basis of the calculation: 100g

For Carbon:
Mass of carbon = (100 g)(0.80) = 80 g
Number of moles of carbon = (80 g)(1 mole / 12g) = 20/3

For Hydrogen:
Mass of hydrogen = (100 g)(0.20) = 20 g
Number of moles of hydrogen = (20 g)(1 mole / 1 g) = 20

Translating the answer to the formula of the substance,
C20/3H20

Dividing the answer,
CH3

The molar mass of the empirical formula is:
12 + 3 = 15 g/mol

Since, the molar mass given for the molecular formula is 30.069 g/mol, the molecular equation is,
C2H6

ANSWER: C2H6

4 0

4 years ago

A sample of gas (1.9 mol) is in a flask at 21 °C and 697 mm Hg. The flask is opened and more gas is added to the flask. The new

Artyom0805 [142]

Answer: There are now 2.07 moles of gas in the flask.

Explanation:

$PV=nRT$

P= Pressure of the gas = 697 mmHg = 0.92 atm (760 mmHg= 1 atm)

V= Volume of gas = volume of container = ?

n = number of moles = 1.9

T = Temperature of the gas = 21°C=(21+273)K= 294 K (0°C = 273 K)

R= Value of gas constant = 0.0821 Latm\K mol

$V=\frac{nRT}{P}=\frac{1.9\times 0.0821 \times 294}{0.92}=49.8L$

When more gas is added to the flask. The new pressure is 775 mm Hg and the temperature is now 26 °C, but the volume remains same.Thus again using ideal gas equation to find number of moles.

$PV=nRT$

P= Pressure of the gas = 775 mmHg = 1.02 atm (760 mmHg= 1 atm)

V= Volume of gas = volume of container = 49.8 L

n = number of moles = ?

T = Temperature of the gas = 26°C=(26+273)K= 299 K (0°C = 273 K)

R= Value of gas constant = 0.0821 Latm\K mol

$n=\frac{PV}{RT}=\frac{1.02\times 49.8}{0.0821\times 299}=2.07moles$

Thus the now the container contains 2.07 moles.

6 0

3 years ago