Answer:
6) For 0.04392 moles BaSO4 we need 0.02196 moles Na2SO4
To produce 0.02196 moles Ba2SO4 and 0.04392 moles Na2SO4
7) For 16.08 moles LiOH we'll have 8.04 moles H2SO4 produced.
We need 8.04 moles Li2SO4 and 8.04 moles H2O
8) For 0.0206 moles silvernitrate we'll hace 0.0206 moles silver
9) For 0.014 moles of Cu we'll have 0.014 moles Cu(NO3)2
Explanation:
6. Barium sulfate and and sodium sulfate react in a double displacement reaction. If the reaction starts with 10.25 grams of barium sulfate what are the products and how many moles of each product is produced?
Step 1: Data given
Mass of BaSO4 = 10.25 grams
Molar mass = 233.38 g/mol
Step 2: The balanced equation
2BaSO4 + Na2SO4 → Ba2SO4 + 2NaSO4
Step 3: Calcuate moles BaSO4
Moles BaSO4 = 10.25 grams / 233.38 g/mol
Moles BaSO4 = 0.04392 moles BaSO4
Step 4: Calculate moles
For 2 moles BaSO4 we need 1 mol Na2SO4 to produce 1 mol Ba2SO4 and 2 moles NaSO4
For 0.04392 moles BaSO4 we need 0.04392/2 = 0.02196 moles Na2SO4
To produce 0.02196 moles Ba2SO4 and 0.04392 moles Na2SO4
7. Calculate the moles of Li2SO4that would be needed to produce 385 g of LiOH.
Step 1: Data given
Mass of LiOH = 385 grams
Molar mass of LiOH = 23.95 g/mol
Step 2: The balanced equation
Li2SO4 + 2H2O → 2LiOH + H2SO4
Step 3: Calculate moles LiOH
Moles LiOH = 385.0 grams / 23.95 g/mol
Moles LiOH = 16.08 moles LiOH
Step 4: Calculate moles
For 1 mol Li2SO4 we need 2 moles H2O to produce 2 moles LiOH and 1 mol H2SO4
For 16.08 moles LiOH we'll have 8.04 moles H2SO4 produced.
We need 8.04 moles Li2SO4 and 8.04 moles H2O
8. Silver nitrate reacts with copper in a single displacement reaction. To produce copper (1)
nitrate and silver. If 3.50 g of silver nitrate are reacted with excess copper. How many mole of silver would be produced?
Step 1: Data given
Mass of AgNO3 = 3.50 grams
Molar mass of AgNO3 = 169.87 g/mol
Step 2: The balanced equation
Cu + 2AgNO3 → Cu(NO3)2 + 2Ag
Step 3: Calculate moles AgNO3
Moles AgNO3 = 3.50 grams / 169.87 g/mol
Moles AgNO3 = 0.0206 moles
Step 4: Calculate moles of Ag
For 1 mol copper, we need 2 moles of silvernitrate to produce 1 mol of coppernitrate and 2 moles of silver
For 0.0206 moles silvernitrate we'll hace 0.0206 moles silver
9. (Use the chemical equation from above) How many moles of copper (1) nitrate ]can be produced with and 0.89 grams of copper metal?
Step 1: Data given
Mass of Cu = 0.89 grams
Molar mass of Cu = 63.55 g/mol
Step 2: The balanced equation
Cu + 2AgNO3 → Cu(NO3)2 + 2Ag
Step 3: Calculate moles Cu
Moles Cu =0.89 grams / 63.55 g/mol
Moles Cu = 0.014 moles
Step 4: Calculate moles of Coppernitrate
For 1 mol copper, we need 2 moles of silvernitrate to produce 1 mol of coppernitrate and 2 moles of silver
For 0.014 moles of Cu we'll have 0.014 moles Cu(NO3)2
